Answer:
x = 2
Step-by-step explanation:
Given the equation as;
log 3 + log x - log(x + 1) = log 2
collect like terms
log x - log(x + 1) = log 2-1og 3
Re-write the equation by applying laws of logarithms in that when you subtract logs you divide the numbers/terms. This will give
log [ x / x+1 ] = log [2/3]
Cancel log on both sides to remain with;
x/ x+1 = 2/3
Apply cross-product
3{x} = 2{x+1}
3x = 2x + 2
3x-2x = 2
x = 2
<span>x = -2.375 Hopefully that helps :)</span>
Answer:
241,920 different ways
Step-by-step explanation:
We have 6 vowels, but A repeats twice and I repeats three times, so the number of ways in which each can either start or end the word:
³P₂ = 3! / (3 - 2)! = 6 / 1 = 6 ways
You can start words with A, E or I, or end the words with A, E, or I.
the remaining 8 consonants can be arranged in 8! ways = 40,320 ways
total number of ways that the letters can be arranged = 6 x 40,320 = 241,920 different ways
