Solve. log 3 + log x - log(x + 1) = log 2 Please please help

Mathematics

1 answer:

weqwewe [10]2 years ago

8 0

Answer:

x = 2

Step-by-step explanation:

Given the equation as;

log 3 + log x - log(x + 1) = log 2

collect like terms

log x - log(x + 1) = log 2-1og 3

Re-write the equation by applying laws of logarithms in that when you subtract logs you divide the numbers/terms. This will give

log [ x / x+1 ] = log [2/3]

Cancel log on both sides to remain with;

x/ x+1 = 2/3

Apply cross-product

3{x} = 2{x+1}

3x = 2x + 2

3x-2x = 2

x = 2

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% slope = m
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Aleksandr [31]

Answer:

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Step-by-step explanation:

Given

$Spinner = \{1,2,3,4\}$

Array:

$\begin{array}{ccccc}{} & {1} & {2} & {3} & {4} & {1} & {} & { } & { } & {5} & {2} & { } & {} & { } & { } & {3} & {4} & { } & {} & { } & {4} & { } & {6} & { } & {} \ \end{array}$

Required

Complete the blanks

To do this, we simply add up corresponding row and column elements.

$\begin{array}{ccccc}{} & {1} & {2} & {3} & {4} & {1} & {} & { } & { } & {5} & {2} & { } & {} & { } & { } & {3} & {4} & { } & {} & { } & {4} & { } & {6} & { } & {} \ \end{array}$

So, we have:

$\begin{array}{ccccc}{} & {1} & {2} & {3} & {4} & {1} & {1+1} & {1+2 } & {1+3 } & {4} & {2} & {2+1 } & {2+2} & {2+3 } & {2+4 } & {3} & {4} & {3+2 } & {3+3} & {3+4 } & {4} & {4+1 } & {6} & {4+3 } & {4+4} \ \end{array}$

Add

$\begin{array}{ccccc}{} & {1} & {2} & {3} & {4} & {1} & {2} & {3} & {4} & {5} & {2} & {3} & {4} & {5} & {6} & {3} & {4} & {5} & {6} & {7} & {4} & {5} & {6} & {6} & {8} \ \end{array}$