Solve.
log 3 + log x - log(x + 1) = log 2
Please please help
1 answer:
Answer:
x = 2
Step-by-step explanation:
Given the equation as;
log 3 + log x - log(x + 1) = log 2
collect like terms
log x - log(x + 1) = log 2-1og 3
Re-write the equation by applying laws of logarithms in that when you subtract logs you divide the numbers/terms. This will give
log [ x / x+1 ] = log [2/3]
Cancel log on both sides to remain with;
x/ x+1 = 2/3
Apply cross-product
3{x} = 2{x+1}
3x = 2x + 2
3x-2x = 2
x = 2
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