Answer:
Step-by-step explanation:
<u>6-digit palindrome is the number n the form of:</u>
<u>This is divisible by 11 by default as the sum of the digits in odd placed is same as sum of the number in even places (remember the divisibility rule by 11):</u>
Now, in order to be divisible by 99, the number must be divisible by 11 and 9.
According to divisibility rule by 9 the sum of all digits must be divisible by 9. <u>You can see In our case we need to have (the minimum):</u>
<u>The smallest number we could get is when x is minimum, y is minimum, so:</u>
<u>The number we get is:</u>
<u>Proof:</u>
Answer:
Step-by-step explanation:
for the first one is
Domain:
(−∞,∞),{x|x∈R}
Range:
(−7,∞),{y|y>−7}
Horizontal Asymptote:
y=−7
y-intercept(s):
(0,−6)
the second one is
y-intercept(s):
(0,8)
Horizontal Asymptote:
y=2
Domain:
(−∞,∞),{x|x∈R}
Range:
(2,∞),{y|y>2}
Answer:
$5.80
Step-by-step explanation:
butterscotch + milk
butterscotch:
$1/5 = $0.20 x 4 = $0.80
milk:
$1 x 5 = $5
$5 + $0.80 = $5.80
Answer:
C
Step-by-step explanation:
Because you should be subtract each other by 20x to transfer from side to another side.
Answer:
3.73 hours
Explanation:
In 1 hour, Lisa does 1/7th of the order while Bill does 1/8th of the order in an hour. To find out how long it will take them to fill the order, we have to:
Step 1:
Add the rate of both Lisa and Bill together
1/7 + 1/8
Step 2:
Since both denominators of the fractions are different, you have to find the least common multiple of 7 and 8
7·8= 56 8·7= 56
which is 56.
Step 3:
Then, you have to multiply the numerator of 1/7 with 8 and the numerator of 1/8 with 7.
1·8= 8 1·7= 7
The fractions would now have equal denominators:
Lisa: 8/56 Bill: 7/56
Step 4:
Now, you can add them together
8/56 + 7/56
which equals to 15/56. Both Lisa and Bill together completes 15/56th of the order in 1 hour.
Step 5:
15/56 is not the final answer as it is the RATE of them working together. To find how long it will take them total to complete the order, you must divide 56 with 15.
56/15
which is 3.73 hours in decimal form (rounded).
