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VLD [36.1K]
3 years ago
14

A direct variation function obtains the points (-8,-6) and (12,9). Which equation represents the function

Mathematics
1 answer:
emmasim [6.3K]3 years ago
8 0
We know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form or
With the point 1 or the point 2 find the value of the constant k
Point 1 (-8,-6)
x=-8
y=-6
substitute
y/x=k
-6/-8=k
k= 3/4

therefore
the equation is
y= 3/4x
the answer is the option
y= 3/4x
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Do the following proofs
Anna11 [10]

1) By the SSS postulate we can tell that these two triangles are congruent.

-> What is SSS?

[] When three sides of a triangle are congruent to the three sides of another triangle, then the two triangles are said congruent by side-side-side

[] The proof for the assignment

AB = DF, AC = DE, BC = EF    |    Given

The triangles are congruent   |    SSS Postulate

2) We can use AAS for these two triangles.

-> What is AAS?

[] When one side and two angles of a triangle are congruent to one side and two angles of another triangle, then the two triangles are said congruent by angle-angle-side

-> How does this apply here?

[] We are given that two angles are congruent to each other, so the angle-angle part is solved for. Since these two triangles share a side, that side will be congruent for each triangle, giving us angle-angle-side

[] The proof for the assignment

Angle T = angle N, angle TAB = angle NAB   |   Given

AB = AB   |    Reflexive Property

The triangles are congruent   |   AAS Postulate

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0
2 years ago
The double box plot shows the test scores for Miss Robinson's second and fourth period
Afina-wow [57]

Answer: The second period class has the greater first quartile.

4 0
3 years ago
Find the slope of each of the lines below:
kolezko [41]
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Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ
enot [183]

2x - 3y = - 13

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

First obtain the equation in slope-intercept form

y = mx + c ( m is the slope and c the y-intercept )

calculate m using the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 5 ) and (x₂, y₂ ) = (- 2, 3 )

m = \frac{3-5}{-2-1} = \frac{-2}{-3}= \frac{2}{3}

y = \frac{2}{3} x + c ← partial equation

to find c substitute either of the 2 points into the partial equation

using (1, 5 ), then

5 = \frac{2}{3} + c ⇒ c = \frac{13}{3}

rearrange the equation into standard form

multiply through by 3

3y = 2x + 13 ( subtract 3y and 13 from both sides )

2x - 3y = - 13 ← in standard form


3 0
3 years ago
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I think it is already reduced.

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