The question is incomplete. Here is the complete question.
m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.
If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.
A. 1
B. 154
C. 77
D. 26
Answer: B. m∠K = 154
Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.
Related to internal angles, angles of the base are equal and opposite angles are supplementary.
In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:
18x + 8 = 11x + 15
7x = 7
x = 1
Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:
m∠J = 18(1) + 8
m∠J = 26
m∠K + m∠J = 180
m∠K + 26 = 180
m∠K = 154
The angle m∠K is 154°
8x = 54 - 6.
Then lets solve the equation. :)
8x = 48.
x = 6.
Hope it helps! :)
D: because if you take 9.50-7.50=2 you would get p=price or the price of the pen.
Hope I helped=)
Simple...
change them all into fractions or decimals...
0.7---> 0.7
-->>0.77
--->>0.875
Ordering from greatest to least....
0.875-->>0.77-->>0.7
-->>
-->>0.7
Thud, your answer.
Answer: 288
Workings : 16 x 12 =192 (for bottom rectangle bit) 12x 16 =192 then divide 192 by 2 =96 add them together and its 288
