Tigers:-
f(t) = 7(1 + 0.1)^2 where t = number of years
Eagle
g(t) = 15 + 2t
B after ten year number tigers = f(t) = 7(1 + 0.1)^10 = 18
number of eagles = 15 + 10(2) = 35
C when the number of tigers = number eagles the 2 functions will be equal;-
f(t) = g(t) that is:-
7* 1.1^t = 15 + 2t
solve for t
You need a picture of the data table...
2.2x and 4.4 have a GCF of 2.2. So, you can factor that out like so:
2.2x+4.4 = 2.2*x+2.2*2 = 2.2(x+2)
Hope this helps!
|
|__x_- 4___________ 2x³/2x² =x
2x² + 2x +3 | 2x³ - 6x² +7x +3
- (<span>2x³ +2x² +3x)
</span> -8x² +4x +3 -8x²/2x² = -4
<span>-(-8x² -8x -12)
</span> 12x +15
(x-4) + (12x +15)/(2x² + 2x +3)
Children=x
Adults=y
* x + y =275 => x = 275 - y
* 3.00x + 6.40y = 1284 <=> 3.00(275 - y) + 6.40y = 1284 <=> ... <=> y = 135 => x = 275 - 135 = 140
Children: 140
Adults: 135
