The pyramid is shown in the diagram below.
The pyramid is built from four congruent triangles and one square as the base
We have the side of the square, so the area is = 10×10 = 100
We need the height of the triangle to work out its area. We can find out by using the height of the pyramid and half of the length of the side of the square.
Using the Pythagoras rule
Height of triangle =

Area of one triangle = 1/2×10×12=60
Surface area of the pyramid = 100 + (4×60) = 340 square inches
Answer:
7
Step-by-step explanation:
= 7
Answer:
I sure hope none is an answer because none of these work!
Step-by-step explanation:
C = 59 (F - 32)
(C/59) = F - 32
F = C/59 + 32
So no :(
m = x + y + z3
y = m - x - z3
So no :((
s = r^2 - 1
r = sqrt(s+1)
So no :000
A = 12(a+b)
A = 12a + 12b
12b = A - 12a
b = A/12 - a
So no :00(((
m = x + y^2
y = sqrt (m-x)
AND no :|
Answer:
5
Step-by-step explanation:
A 30-60-90 triangle's sides equal as follows:
Hypotanuse= x (a number)
Long side= x/2( also can be calculated as x* 1/2) * 
Short side = x/2 or x * 1/2
The answer is A) 8/17
sine is opposite/hypotenuse
thus, if you used angle C, opposite of that is segment AB. the hypotenuse is is segment AC as it is opposite of the right angle.
m of segment AB is 8
m of segment AC is 17
thus the sine of
hope i helped :)