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3 years ago

Which expression is equivalent to b * b * b * b *

Mathematics

1 answer:

Ne4ueva [31]3 years ago

4 0

Answer:

b⁴

Explanation:

b×b=b² b×b=b²

b²×b=b³ b×b×b=b³

b³×b=b⁴ b×b×b×b=b⁴

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Two straight lines VZ and YW intersect at X

Alexeev081 [22]

Answer:

∠WVX = 35°

Step-by-step explanation:

Look at the rough draw.

As you can see,

VW ║ YZ

So ∠XWV is congruent to ∠XYZ through alternate interior angle.

We can solve ∠WVX by considering the two other angles, 88° and 57°.

Total angle of a triangle is 180°.

So,

? + 88 + 57 = 180

? + 145 = 180

? = 180 - 145

? = 35°

5 0

4 years ago

Been waiting for half an hour pls help me

Stella [2.4K]

Answer:

13.7 cm

Step-by-step explanation:

there are 360° in a circle and in this image, we can see 90°+90°+66.4°=260.4
since we know that 360°-260.4°=99.6°
The angle measure of arc AD is 99.6°

Now that we covered that, we can use the arc length formula in order to find the length of arc AD.

arc length = 2πr(Θ/360°)
2π(7.9)(99.6°/360°) = 13.7329
rounded to the nearest tenth = 13.7

3 0

3 years ago

75km/h compute in m/s

Vlad1618 [11]

75 * 1000/3600 = 20.8333333

You just need to multiply with 1000 to get m from km and divide by 3600 because you are converting hours in seconds.

8 0

3 years ago

A bag contains 7 red marbles, 3 blue marbles, 1 green what is the prob. of choosing a marble not blue?

Alex787 [66]

3 marbles as there is only one green and there is three other blue marbles left and that answer is incorrect

8 0

3 years ago

Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6

Alla [95]

Given:

The expression is:

$2x^3+mx^2+nx+c$

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

$m+n=-6$

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

$P(x)=2x^3+mx^2+nx+c$

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

$P(2)=P(-1)$ ...(i)

Substituting $x=-1$ in the given polynomial.

$P(-1)=2(-1)^3+m(-1)^2+n(-1)+c$

$P(-1)=-2+m-n+c$

Substituting $x=2$ in the given polynomial.

$P(2)=2(2)^3+m(2)^2+n(2)+c$

$P(2)=2(8)+m(4)+2n+c$

$P(2)=16+4m+2n+c$

Now, substitute the values of P(2) and P(-1) in (i), we get

$16+4m+2n+c=-2+m-n+c$

$16+4m+2n+c+2-m+n-c=0$

$18+3m+3n=0$

$3m+3n=-18$

Divide both sides by 3.

$\dfrac{3m+3n}{3}=\dfrac{-18}{3}$

$m+n=-6$

Hence proved.

7 0

3 years ago