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3 years ago

What’s the interger of -(-10)

Mathematics

1 answer:

Lorico [155]3 years ago

7 0

Answer:

Step-by-step explanation:

A negative number with another negative sign is practically a positive number.

Example: -(-4)

-(-4)

-1 * -4

Question: -(-10)

-(-10)

-1 * -10

10

Answer: 10

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Alex777 [14]

Answer:

there is no pic lol

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help thank you!!!

rusak2 [61]

Answer:

K' (-1,10)

L'(0,4)

M'(2,2)

Step-by-step explanation:

To use the mapping rule, substitute x and y with the original values

The coordinates of K are x=-4, and y=5.

Using the mapping rule, x of K' = -4+3 = -1

Using the mapping rule y of K' = 2x5=10

So K' is at the coordinate (-1,10)

The coordinates of L are x =-3, and y =2.

Using the mapping rule, x of L' = -3+3=0

Using the mapping rule y of L' = 2x2=4

So L' is at the coordinate (0,4)

The coorindates of M are x=-1 and y=1

Using the mapping rule, x of M' = -1+3=2

Using the mapping rule, y of M' = 2x1 = 2

So M' is at the coordinate (2,2).

8 0

3 years ago

A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of

Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

Step-by-step explanation:

Let X = time spent per week shopping online.

It is provided that the random variable X follows a Poisson distribution.

The probability function of a Poisson distribution is:

$P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...$

The average time spent per week shopping online is, λ = 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

$P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217$

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338$

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

$=\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922$

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

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4 years ago

Elle has a sticker book with 12 pages of stickers. Her friend Erin's book has 3 times more pages. How many pages are in Erin's b

Fed [463]

Answer:

36 pages

Step-by-step explanation:

12 multiplied by 3 is 36

5 0

3 years ago

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In an Animal shelter, the ratio of dogs to cats is 5 to 3. There are 25 dogs, how many cats are there?

LekaFEV [45]

Answer: 25:15

Step-by-step explanation: in the ratio 5:3 the 5 is dogs and the 3 is cats you multiply the 5 (aka the dogs) by 5 to get 25 (the amount of dogs in the shelter) when you multiply 3 by 5 you get the amount of cats which is 15, a good way to remember is what you do to one side you have to do to the other. I hope this helps.

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3 years ago