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2 years ago

8

A store sold 655 bicycles last year. This year the store sold 582 bicycles. What is the percent of change in the number of bicyc

les sold from last year to this year? Round to the nearest percent

1 answer:

Triss [41]2 years ago

7 0

Answer:

12.5%

Step-by-step explanation:

Given data

Number of bicycles sold last year= 655

Number of bicycles sold this year= 582

%percent change= Iniitial -FInal/initial *100

%percent change= 655-582/582*100

%percent change= 73/582 *100

%percent change=0.125 *100

%percent change=12.5%

Hence the percent change is 12.5%

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[10 Points, Algebra 2]

tensa zangetsu [6.8K]

5/ 1+1= 5/2
1+4/1^2-3(1)-4= 5/-6

5/2 - 5/-6 does not equal zero

4 0

3 years ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

as

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

3 years ago

market price of a dress is 1500 rupees shop owner give a discount of 20% find the discount and the bill amount paid

kogti [31]

Step-by-step explanation:

Marked price (mp) =rs 1500

discount (d) = 20%

discount amount = d% of mp

=20/100 *1500

= Rs. 300

bill amount paid = mp -d

= 1500 - 300

= Rs. 1200

3 0

2 years ago

GuDViN [60]

Answer:

5x - y = 27

Step-by-step explanation:

Slope is the direction of line and it is calculated as,

$Slope = \frac{y-y_{1}}{x-x_{1}}
$

where (x₁, y₁) is any two points on the line.

Here, we have given that

Slope = 5 and (x₁, y₁) = (5, -2)

∴ $5 = \frac{y-(-2)}{x-5}
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⇒ 5(x - 5) = y + 2

⇒ 5x - 25 = y + 2

⇒ 5x - y = 27

Hence, the equation of a line is: 5x - y = 27

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2 years ago

Hello, please help me with this as well, but show me example how you worked it out?<br><br> 33 + - 5

ANTONII [103]

Answer: 28

Step-by-step explanation: A positive (+) and a negative (-) together make it a negative (-) which takes the positive away (+) making it 33 - 5 = 28

4 0

2 years ago

Read 2 more answers