We begin with an unknown initial investment value, which we will call P. This value is what we are solving for.
The amount in the account on January 1st, 2015 before Carol withdraws $1000 is found by the compound interest formula A = P(1+r/n)^(nt) ; where A is the amount in the account after interest, r is the interest rate, t is time (in years), and n is the number of compounding periods per year.
In this problem, the interest compounds annually, so we can simplify the formula to A = P(1+r)^t. We can plug in our values for r and t. r is equal to .025, because that is equal to 2.5%. t is equal to one, so we can just write A = P(1.025).
We then must withdraw 1000 from this amount, and allow it to gain interest for one more year.
The principle in the account at the beginning of 2015 after the withdrawal is equal to 1.025P - 1000. We can plug this into the compound interest formula again, as well as the amount in the account at the beginning of 2016.
23,517.6 = (1.025P - 1000)(1 + .025)^1
23,517.6 = (1.025P - 1000)(1.025)
Divide both sides by 1.025
22,944 = (1.025P - 1000)
Add 1000 to both sides
23,944 = 1.025P
Divide both by 1.025 for the answer
$22,384.39 = P. We now have the value of the initial investment.
For graphing make sure to shade the right portion and to make the line dotted like (— — — —)
the red is y>8x-4, the blue is y>-1/2x+1/2
2x-.25y < 1 is equal to 2x-1/4y < 1
multiply each side by 4:
8x-y < 4
add y to each side:
8x < 4+y
subtract 4 from each side:
8x-4 < y
rewrite:
y > 8x-4
4x+8y > 4
divide both sides by 8:
1/2x+y > 1/2
subtract -1/2x from each side:
y > -1/2x + 1/2
Step-by-step explanation:
I think I did the right process but the answer didn't match.
Answer:
I believe the answer is A
Step-by-step explanation:
Answer:
x = 26/15
Step-by-step explanation:
is means equals
52 / x = 30
Multiply each side by x
52 = 30x
Divide each side by 30
52/30 = x
26/15 = x
