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Simora [160]
3 years ago
5

6x^{2} + 19 + 9x^{2} - 8 With Explanation

Mathematics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

I'mnot sure if you're asking for its roots..but here you go :)

Step-by-step explanation:

= 6 {x}^{2} + 19 + 9 {x}^{2}   - 8 \\  = (6 {x}^{2}  + 9 {x}^{2} ) + (19 - 8) \\  = 15 {x}^{2}  + 8 \\ 15 {x}^{2}  =  - 8 \\  {x}^{2}  =   - \frac{8}{15} \\  \sqrt{ {x}^{2} }  =  \sqrt{  - \frac{8}{15} }   \\ x =  \sqrt{ \frac{8}{15}}  \times  \sqrt{ - 1}  \\ x =  \sqrt{ \frac{8}{15} }  \times i \\  x1 = 0.7302i \\ x2 =  - 0.7302i

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Gcf of 12 and 15 please help me.......
aivan3 [116]

Answer:3

Step-by-step explanation:the answer is 3 I did the math

5 0
3 years ago
Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers
Alenkinab [10]

Given:

\sigma_A=3

n_A=6

\sigma_B=5

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\overline{x}_A=\overline{x}_B

To find:

The variance. of combined set.

Solution:

Formula for variance is

\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}      ...(i)

Using (i), we get

\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}

(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}

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54=\sum (x_i-\overline{x}_A)^2

Similarly,

\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}

(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}

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100=\sum (x_i-\overline{x}_B)^2

Now, after combining both sets, we get

\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}

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7 0
3 years ago
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lora16 [44]

Answer:

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Step-by-step explanation:

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3 years ago
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svetoff [14.1K]
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3 years ago
Read 2 more answers
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