You would use PEMDAS
But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57
Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57
Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57
Now you can add all of the numbers together
32➕504=536
536➕57=593
Your answer is 593
Hope this helps! :3
Ahh I’m not smart so imma just guess not saying it’s right . 24 in?
Step-by-step explanation:
I think the answer is 3x square multiplied by 1
Coz anything raised to power 0 will always equal to 1
Answer:
<h2>[-4, 6)</h2>
Step-by-step explanation: