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Sonbull [250]
3 years ago
8

I need help,Im doing a quiz,pls help me quick,this is the question:

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

Answer: You will need to add all the number up

Step-by-step explanation:

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What is the value of this expression when a = 3 and b = -2?
weqwewe [10]

The first step: Simplify the expression with:

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\left(\dfrac{3a^{-2}b^6}{2a^{-1}b^5}\right)^2=\left(\dfrac{3}{2}a^{-2-(-1)}b^{6-5}\right)^2=\left(\dfrac{3}{2}a^{-1}b^1\right)^2\\\\=\left(\dfrac{3}{2}\right)^2(a^{-1})^2b^2=\dfrac{9}{4}a^{-2}b^2=\dfrac{9b^2}{4a^2}

The second step: Put the values of a = 3 and b = -2 to the expression:

\dfrac{9(-2)^2}{4(3)^2}=\dfrac{(9)(4)}{(4)(9)}=1

<h2>Answer: 1</h2>
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4 years ago
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If the dividend is a whole number and the divisor is 3.68 how do you move the decimal point for the dividend?
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3 years ago
F(x)=7x+7 and g(x)=6x^2<br> find (fg)(x)
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