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Gnom [1K]
2 years ago
9

(02.02 MC) Triangle ABC is shown. A is at negative 2, 1. B is at negative 1, 4. C is at negative 4, 5. If triangle ABC is reflec

ted over the x‐axis, reflected over the y‐axis, and rotated 180 degrees, where will point B' lie? (−1, 4) (1, −4) (4, −1) (−4, 1)
Mathematics
1 answer:
Bezzdna [24]2 years ago
6 0

Given:

The vertices of a triangle ABC are A(-2,1), B(-1,4) and C(-4,5).

Triangle ABC is reflected over the x‐axis, reflected over the y‐axis, and rotated 180 degrees.

To find:

The point B'.

Solution:

If a figure reflected over x-axis, then

(x,y)\to (x,-y)

B(-1,4)\to B_1(-1,-4)

If a figure reflected over y-axis, then

(x,y)\to (-x,y)

B_1(-1,-4)\to B_2(-(-1),-4)

B_1(-1,-4)\to B_2(1,-4)

If a figure rotated 180 degrees about the origin, then

(x,y)\to (-x,-y)

B_2(1,-4)\to B'(-(1),-(-4))

B_2(1,-4)\to B'(-1,4)

So, the coordinate of point B' are (-1,4).

Therefore, the correct option is A.

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4 0
2 years ago
Read 2 more answers
Write the equation of the line that passes through the points (2,0) and (1,-2)
Darya [45]

Answer:

y

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer linky

=

2

x

−

1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

m

is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

y

2

)

For this problem the slope is:

m

=

3

−

−

1

2

−

0

m

=

3

+

1

2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

Solving for

y

to put this in standard form gives:

y

+

1

−

1

=

2

x

−

1

y

+

0

=

2

x

−

1

y

=

2

x

−

1

Answer link

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