All categories

3 years ago

a rectangle has a perimeter of 68 inches.if the width of the rectangle is 10 inches,what is the length of the rectangle?

Mathematics

2 answers:

Dmitriy789 [7]3 years ago

3 0

Answer:

l=24in

Step-by-step explanation:

P=2(l+w)

l=P

2﹣w=68

2﹣10=24in

taurus [48]3 years ago

3 0

24 inches because if you add the two width you get 20 and then do the equation 68-20=48. Divide that by 2 and then you get 24 so then that’s the length

You might be interested in

Exponential Function:

vovangra [49]

Answer:

See below

Step-by-step explanation:

On the graphs we see transformations of exponential functions

<h3>Graphic 1 = Horizontal shift </h3>

f(x) = 2ˣ is the parent function
g(x) = 2ˣ⁺³ indicates shift to the left by 3 units
h(x) = 2ˣ⁻¹ indicates the shift to the right by 1 unit

<h3>Graphic 2 =Vertical shift</h3>

p(x) = (1/3)ˣ is the parent function
r(x) = (1/3)ˣ⁺³ indicates shift up by 3 units
q(x) = (1/3)ˣ⁻² indicates the shift down by 2 units

4 0

4 years ago

In a problem it says that x is "at most –5." What does this mean?

STatiana [176]

It means that -5 is the range of your answer, it will be less than that.

8 0

3 years ago

Read 2 more answers

A conical pile of road salt has a diameter of 112 feet and a slant height of 65 feet. After a storm, the linear dimensions of th

QveST [7]

we know that

the volume of a cone is equal to

$V= \frac{1}{3} \pi r^{2}h$

in this problem

the radius is equal to

$r= \frac{112}{2}= 56ft$

1) Find the height of the cone before the storm

Applying the Pythagorean Theorem find the height

$h^{2} = l^{2}-r^{2}$

$l=65 ft$

$h^{2} = 65^{2}-56^{2}$

$h^{2} = 1,089$

$h=33 ft$

2) Find the volume before the storm

$V= \frac{1}{3}*\pi* 56^{2}*33$

$V=34,496\pi\ ft^{3}$

3) Find the volume after the storm

After a storm, the linear dimensions of the pile are 1/3 of the original dimensions

r=(56/3) ft

h=(33/3)=11 ft

$V= \frac{1}{3}*\pi* (56/3)^{2}*11$

$V= 1,277.63\pi\ ft^{3}$

4) Find how this change affect the volume of the pile

Divide the volume after the storm by the volume before the storm

$\frac{1,277.63 \pi }{34,496 \pi } = \frac{1}{27}$

therefore

the answer part a) is

The volume of the pile after the storm is $\frac{1}{27}$ times the original volume

Part b) Estimate the number of lane miles that were covered with salt

5) Find the amount of salt that was used during the storm

$=34,496 \pi - 1,277.63 \pi \\= 33.218.37 \pi \\= 104,358.59\ ft^{3}$

6) Find the pounds of road salt used

$104,358.59*80=8,348,687.2\ pounds$

7) Find the number of lane miles that were covered with salt

$8,348,687.2/350=23,853.39 \ lane\ miles$

therefore

the answer part b) is

the number of lane miles that were covered with salt is $23,853.39 \ lane\ miles$

Part c) How many lane miles can be covered with the remaining salt? Round your answer to the nearest lane mile

the remaining salt is equal to $1,277.63\pi\ ft^{3}$

$1,277.63\pi\ ft^{3}=4,013.79\ ft^{3}$

8) Find the pounds of road salt

$4,013.79*80=321,103.20\ pounds$

9) Find the number of lane miles

$321,103.20/350=917.44 \ lane\ miles$

therefore

the answer part c) is

the number of lane miles is $917 \ lane\ miles$

7 0

4 years ago

Two sides of a triangle are equal in length. The third side of the triangle is 3 more than the equal sides. If the perimeter of

Inessa [10]

Answer:

Step-by-step explanation:

The two smaller sides are 15 and the larger one is 18

7 0

3 years ago

Read 2 more answers

Let f = {(–2, 4), (–1, 2), (0, 0), (1, –2), (2, –5)}. Let g = {(–3, 3), (–1, 1), (0, –3), (1, –4), (3, –6)}. What is g(f(2))?

pav-90 [236]

The composition is undefined.

4 0

4 years ago

Read 2 more answers