The foci of the hyperbola are ( 13 , 0) and (− 13 , 0), and the asymptotes are y = 12 x and y = − 12 x. find an equation of the
conic section with the given properties. use x and y as the variables in your answer.
1 answer:
Y=k+- a/b(x-h)
y=-+12x
12=a/b
a=12b
c²=a²+b²
(13,0) and (-13,0)
13²=(12b)²+b²
169=145b²
b= 13/12
169=a²+169/145
a²= 24336/145
x²/a²-y²/b²=1
145x²/24336 + 145y²/169=1
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Have a good day
Answer:
The value of x is 4√2 and y is 2√6
I hope it helps
F(x)= √3x + 1
a=8
8 √3 + 1 <—Exact form
14.85649646 <—In decimal form