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-BARSIC- [3]
3 years ago
5

The foci of the hyperbola are ( 13 , 0) and (− 13 , 0), and the asymptotes are y = 12 x and y = − 12 x. find an equation of the

conic section with the given properties. use x and y as the variables in your answer.
Mathematics
1 answer:
kupik [55]3 years ago
5 0
Y=k+- a/b(x-h)

y=-+12x

12=a/b

a=12b

c²=a²+b²

(13,0) and (-13,0)

13²=(12b)²+b²

169=145b²

b= 13/12

169=a²+169/145

a²= 24336/145

x²/a²-y²/b²=1

145x²/24336 + 145y²/169=1



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Step-by-step explanation:

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30/126 = 5/21 paid by debit card.

77/126 = 11/18 paid by credit card.

next week he expects 1800 customers.

that is compared to 126 a factor of

1800/126 = 300/21 = 100/7

now we actually only need to apply the same factor to any part of the total sum to get their share in the new total sum.

it simply follows the rule

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2 years ago
What is it then please
nalin [4]

a) because the denominators are the same add the numerators:

1 1/5 + 3 2/5 = 4 3/5

b) rewrite the fractions to have a common denominator:

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Now subtract:

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3 years ago
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Point A(-2, -2) and B(3, -2) are dilated with the center of dilation at C(0, 0) and k=2.
frez [133]

9514 1404 393

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  A'(-4, -4), B'(6, -4), parallel

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AnnZ [28]

Answer:

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Step-by-step explanation:

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Solve over the set of real numbers for the equation below x-2=√2x-1
Anon25 [30]

The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.

<h3>What is the solution of the equation?</h3>

The solution of the equation means the value of the unknown or variable.

The equation is given below.

x – 2 = √(2x – 1)

Square on both side, then we have

               (x – 2)² = 2x – 1

         x² – 4x + 4 = 2x – 1

         x² – 6x + 5 = 0

   x² – 5x – x + 5 = 0

x(x – 5) – 1(x – 5) = 0

       (x – 5)(x – 1) = 0

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The set of real numbers for the equation x – 2 = √(2x – 1) will be 5.

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ1

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