Answer:
15
Step-by-step explanation:
H - 7
When H = 22, replace H with 22 in the equation.
22 - 7 = 15
Answer:
A, B, D
Step-by-step explanation:
Use the LCM to help...
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
Answer:
Step-by-step explanation:
(a) You use the fact that the lengths RS and ST total the length RT.
RS +ST = RT
(6y+3) +(3y+5) = 80 . . . . . substitute the given values
9y +8 = 80 . . . . . . . . . . . . .simplify
9y = 72 . . . . . . . . . . . . . . . .subtract 8
72/9 = y = 8 . . . . . . . . . . . .divide by the coefficient of y
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(b) Now, the value of y can be substituted into the expressions for RS and ST to find their lengths.
RS = 6y +3 = 6·8 +3
RS = 51
ST = 3y +5 = 3·8 +5
ST = 29
___
<em>Check</em>
RS +ST = 51 +29 = 80 = RT . . . . the numbers check OK
Answer:
x=9
Step-by-step explanation:
