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Fudgin [204]
3 years ago
10

Write the equation of the

Mathematics
2 answers:
Vladimir79 [104]3 years ago
3 0

Answer:

y=5x+13

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(3-(-2))/(-2-(-3))

m=(3+2)/(-2+3)

m=5/1

m=5

y-y1=m(x-x1)

y-(-2)=5(x-(-3))

y+2=5(x+3)

y=5x+15-2

y=5x+13

Alchen [17]3 years ago
3 0

Answer:

y = 5x + 13

Step-by-step explanation:

Slope = delta y/ delta x

(3-(-2))/(-2-(-3))

(5)/(1) = 5

Slope = 5

y = 5x + b

Find the y-intercept through substitution:

(-2,3)

3 = 5(-2) + b

3 = -10 + b

13 = b

Equation:

y = 5x + 13

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The equation produces a straight line.
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Please help me on this question, I was struggling with it for an hour from now.
krek1111 [17]

Answer:

D

Step-by-step explanation:

P(3) = ⅙

P(5) = ⅙

Trials are independent so,

P(3 then 5) = 1/6 × 1/6 = 1/36

4 0
3 years ago
Evaluate 2.6 raised to the seventh power divided by 2.6 raised to the sixth power, all raised to the second power.
igomit [66]

The evaluation of 2.6 raised to the seventh power divided by 2.6 raised to the sixth power, all raised to the second power is as follows:

(\frac{2.6^{7} }{2.6^{6} } )^{2} = 6.76

<h3>How to evaluate an expression?</h3>

2.6 raised to the seventh power divided by 2.6 raised to the sixth power, all raised to the second power.

The following expression can be evaluated as follows;

(\frac{2.6^{7} }{2.6^{6} } )^{2}

Using the law of indices,

(A^{x} )^{y} = A^{xy}

Therefore,

(\frac{2.6^{7} }{2.6^{6} } )^{2} = (\frac{2.6^{14} }{2.6^{12} } )

Using the law of indices,

\frac{A^{x} }{B^{y} } = A^{x-y}

Hence,

(\frac{2.6^{7} }{2.6^{6} } )^{2} = (\frac{2.6^{14} }{2.6^{12} } ) = 2.6^{14-12}  = 2.6^{2}  = 6.76

Therefore,

(\frac{2.6^{7} }{2.6^{6} } )^{2} = 6.76

The evaluation of 2.6 raised to the seventh power divided by 2.6 raised to the sixth power, all raised to the second power is 6.76.

learn more on expression here: brainly.com/question/28337613

#SPJ1

7 0
2 years ago
Help meeeeee plsssss
Brrunno [24]
Answer: 0.57
It’s out of 100, so it’s 57 hundredths
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3 years ago
PLEASE PLEASE PLEASE HELP ME WITH ALGEBRA 1 PLEASE!?!?!?!?!!!?!?!?!?!?! I WILL GIVE LOTS OF POINTS AND BRAINLEST PLEEEEEEEEEEEEE
Aneli [31]
With graphs on paper you can visually see intersecting lines(one solution), identical lines
(infinite solutions), or parallel lines(no solutions).
This method works best for lines that have integers for solutions. The task of determining rational or irrational solutions from graphs is difficult.

The substitution method usually must be used for equations with higher exponents. The deawback of this method is having to work with fractions.

The elimination method is often the method of choice.
This method however requires that you learn to recognize when the systems produce parallel lines or have equations that represent the same lines.
7 0
3 years ago
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