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Lostsunrise [7]
2 years ago
8

Given the diameter of a circle is 17 1/2cm, find its area (use π = 22/7)​

Mathematics
1 answer:
vladimir2022 [97]2 years ago
6 0

Answer:

240.625 is full value. you can use sigfigs if you need.

Area is (pi)(r)^2 so (22/7)(8.75)^2

half diameter is radius

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Answer:

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Step-by-step explanation:

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3 0
3 years ago
10+2r=8 need the answer now
natulia [17]

Simplifying

10 = 2r + -8

Reorder the terms:

10 = -8 + 2r

Solving

10 = -8 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.

10 + -2r = -8 + 2r + -2r

Combine like terms: 2r + -2r = 0

10 + -2r = -8 + 0

10 + -2r = -8

Add '-10' to each side of the equation.

10 + -10 + -2r = -8 + -10

Combine like terms: 10 + -10 = 0

0 + -2r = -8 + -10

-2r = -8 + -10

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-2r = -18

Divide each side by '-2'.

r = 9

Simplifying

r = 9

3 0
3 years ago
Read 2 more answers
The bank charged TENLEY $30 fee because her balance dropped below $0. She knows that she currently has an outstanding charge of
Korolek [52]

Answer:

Tenley has to deposited any amount from $50 and above.

Step-by-step explanation:

From the above question, we can deduce that if your bank balance is below 0, = - , you would be charged $30

Hence,

First she has to pay the bank charges of $30, and to prevent the outstanding charge of $19.95 for generating about charge she has to deposit any amount above $19.95

The amount she has to deposit is

$30 + (x > $19.95)

Assuming x is $20 and above

= $30 + $20 = $50

Hence, Tenley has to deposited any amount from $50 and above.

7 0
3 years ago
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timama [110]
He would have paid about $1,532 dallors for the car after 4 years than the original price he has to pay for the monthly pay for the car.
4 0
3 years ago
What is the greatest common factor of 200 and 140 
Tanzania [10]
200|2 \\ 100|2 \\ 50 \ |2 \\ 25 \ |5 \\ 5 \ \ |5 \\ 1 \\\\200=2^3*5^2 \\\\ 140|2 \\70 \ |2 \\ 35 \ |5 \\ 7 \ \ |7 \\1 \\\\ 140=2^2*5*7 \\\\ G.C.F(200;140)=2^2*5=20
5 0
3 years ago
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