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3 years ago

1/2(x+2)=5(x+2) solve the following completely

Mathematics

1 answer:

Nikitich [7]3 years ago

3 0

Answer:

X is equalled to '' - 2''

Step-by-step explanation:

If you need an explanation, leave a comment ;) As my hand writing is very messy. I'll write it here if you want.

Cheers! :)

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Ratiearbiteracy

ipn [44]

Explanation

Sorry but You gone have to higher the price for this, this is a big question.

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3 years ago

Slope = 2/5 On a Graph

Anestetic [448]

Look at it as the rise/run. Go up positive 2 on the graph(y-axis) for every 5 that you go across on the graph. Over 5, up 2, over 5, up 2. Hope this helps

8 0

3 years ago

What is 4 plus negative 3

Natalka [10]

4 plus negative 3 is 1.

When adding negative numbers to positive ones, you should treat it as a normal subtraction, so 4-3.

6 0

3 years ago

Read 2 more answers

Bonjour pourriez vous m'aider avec cette équation du second degré? j'ai du mal à comprendre le concept. merci

olga_2 [115]

If a quadratic equation has solutions, the standard procedure will always work: given an equation like

$ax^2+bx+c=0$

The solutions (if any) are given by

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In your case, you have

$a=-9,\ b=0,\ c=1$

So the formula becomes

$x_{1,2} = \dfrac{\pm\sqrt{36}}{18}= \pm\dfrac{6}{18}=\pm\dfrac{1}{3}$

Anyway, this is quite a special case, because you're missing the linear term (since $b=0$ )

This means that you can solve equations like these more easily: rearrange the equation to make it look like $ax^2=c$ . In your case, it becomes

$9x^2=1$

Divide both sides by 9:

$x^2=\dfrac{1}{9}$

Now, you know that the square of a number equals 1/9. By definition, it means that this number is the square root of 1/9. Nevertheless, both the square root and its opposite are solutions of the equation, because the minus sign will cancel out when squaring.

So, in general, you have

$ax^2=c \iff x^2 = \dfrac{c}{a} \iff x=\pm\sqrt{\dfrac{c}{a}$

which of course makes sense, if you're using real numbers, only if c/a>0.

In your case, this becomes

$9x^2=1 \iff x^2 = \dfrac{1}{9} \iff x=\pm\sqrt{\dfrac{1}{9}} = \pm\dfrac{1}{3}$

3 0

3 years ago

In a word problem, instead of calling it the slope, we call it the starting point instead.

Vesnalui [34]

It is true that in a word problem, instead of calling it the slope, we call it the starting point instead.
Although the two terms are interchangeable, in presenting the mathematical question, we need to use the term starting point so as to refer to the place where the slope starts, and not the whole slope.

8 0

4 years ago

Read 2 more answers