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Nataliya [291]
3 years ago
10

Ratiearbiteracy

Mathematics
1 answer:
ipn [44]3 years ago
5 0
Explanation

Sorry but You gone have to higher the price for this, this is a big question.
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Apply the distributive property to factor out the greatest common factor. 18d+12 =18d+12=18, d, plus, 12, equals
kobusy [5.1K]

Answer:

\huge\boxed{6 ( 3d + 2 )}

Step-by-step explanation:

18d + 12

The greatest common factor is 6, So we need to factor out 6

=> 6 ( 3d + 2 ) [Distributive property has been applied and this is the simplest form]

6 0
2 years ago
Read 2 more answers
One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo
almond37 [142]

Answer:

(1) P(\bar X < 26 inches) = 0.0436

(2) P(27.5 inches < \bar X < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let \bar X = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

            Z = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean vertical  leap = 28 inches

            \sigma = standard deviation = 7 inches

            n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P(\bar X < 26 inches)

   P(\bar X < 26) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{26-28}{\frac{7}{\sqrt{36} } } ) = P(Z < -1.71) = 1 - P(Z \leq 1.71)

                                                 = 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < \bar X < 28.5 inches) = P(\bar X < 28.5 inches) - P(\bar X \leq 27.5 inches)

    P(\bar X < 28.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{28.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z < 0.36) = 0.64058 {using z table}                      

    P(\bar X \leq 27.5) = P( \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{27.5-28}{\frac{7}{\sqrt{26} } } ) = P(Z \leq -0.36) = 1 - P(Z < 0.36)

                                                        = 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < \bar X < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0
3 years ago
Paul Zutan scored 73 points. Paul scored 14 more points than Zuban Kawhi scored to as many as Paul How many did Zabar score
Elan Coil [88]
73-14 therefore the answer is 59
6 0
2 years ago
Kayla has a bowl of beads that contains 42 yellow beads, 28 green beads, 12 white beads, and 18 red beads. She randomly draws a
podryga [215]
42 + 28 + 12 + 18 = 100 total beads

probability of not drawing a yellow or a green : (12 + 18) / 100 = 30/100 reduces to 3/10 or 30%

probability of drawing a red or green : (18 + 28) / 100 = 46/100 reduces to
23/50 or 46%


8 0
3 years ago
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4. Show that FD=1/2CB, FE - 1/2AB, and DE = 1/2AC.
lions [1.4K]
Can you take a picture of the problem?
3 0
3 years ago
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