Exponential growth of the form:
F=Ar^t
F=100(1.22)^t
F(5)=100(1.22)^5
F(5)=270.27
F(5)=270 to the nearest frog...
....
1.22=r^12
r=1.22^(1/12)
F=100(1.22^(1/12)^t)
F=100(1.22^(t/12)) now it will produce monthly populations...
Say we did the same as before but instead of 5 years you have 60 months...
F(60)=100(1.22^(60/12))
F(60)=270 to the nearest frog... :P
Answer:
72°
Explanation:
Given that line J and line K are parallel, we can safely assume that line m is the transversal for the following question. We can also remove line l so that we can focus on line m instead.
Using the rule of <u>Alternate Exterior Angle</u> theorem, x would equal to 72°.
If we consider the center of the habitat to be a point - then a circle with a radius of 1.5 km <u /><u />would satisfy the problem.
The path would go around the point (habitiat) and would always be 1.5 km from that point.
Answer:
B.
Step-by-step explanation:
because they have the same base and it's a multiplication so you have to add the exponents
14 patients for each nurse
