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Ksju [112]
3 years ago
15

Is (4, 3) a solution of the graphed inequality?

Mathematics
1 answer:
Maurinko [17]3 years ago
7 0
No it is not. Anything in the shaded area is a solution m. (4,3) is not in the shaded area so it is not a solution for the graphed inequality.
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PLEASE HELP, THANK YOU! :)
elena-s [515]

Steps to solve:

-4z + 4 + 12z = 3z + 4 + 5z

~Combine like terms

8z + 4 = 8z + 4

~Subtract 4 to both sides

8z = 8z

~Divide 8 to both sides

0 = 0

All real numbers are solutions.

Set builder notation: {x | R}

This is an identity since every value can be a solution to the equation.

Best of Luck!

8 0
3 years ago
Using the following image, find GH given HI = 1 and GI =<br> = 9.
shepuryov [24]

Answer:

8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The graph of y=x^2 -7x+ 12 is a parabola with x-intercepts at
vesna_86 [32]

Answer:

<h2>x = 3 and x = 4 → (3, 0) and (4, 0)</h2>

Step-by-step explanation:

\text{x-intercept is for y = 0}.\\\\\text{We have the function:}\ y=x^2-7x+12.\\\\\text{Put y = 0 and calculate the value(s) of x.}\\\\x^2-7x+12=0\\\\x^2-3x-4x+12=0\\\\x(x-3)-4(x-3)=0\\\\(x-3)(x-4)=0\iff x-3=0\ \vee\ x-4=0\\\\x-3=0\qquad\text{add 3 to both sides}\\\boxed{x=3}\\\\x-4=0\qquad\text{add 4 to both sides}\\\boxed{x=4}

6 0
3 years ago
Two circles have the same radius. Is the combined area of the two circles the same as the area of a circle with twice the radius
Dimas [21]
Ok so area=pir^2

2 circles with same area=2pir^2

circle with 2 times radius=pi(2r)^2=pi4r^2=4pir^2

is 2 circles with same area equal to circle with 2 times radius?
is 2pir^2=4pir^2?
is 2=4?
no


therfor the answer is no

it is because the radius is squaered so the doubled gets doubled makng it quadrupuled when the first one only gets doubled
8 0
3 years ago
Finding the percent of increase or decrease
madam [21]
What is the question
4 0
3 years ago
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