1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleksandr-060686 [28]
3 years ago
12

Based on a table provided in your reading material determine the monthly payment for a $100,000 loan if the interest rate is 6%

and the term of the loan is 15 years
Mathematics
1 answer:
kari74 [83]3 years ago
5 0
Answer: The monthly payment on this loan would be $843.86.

Online you can find numerous loan calculators if you don't have access to the one in your reading material. All you need to do is enter the loan amount of $100,000 with a rate of 6% over the course of 15 years.

Entering these values will give a monthly payment of $843.86.
You might be interested in
What is the LCM of 3 and 7
Dima020 [189]

Answer:

The LCM of 3 and 7 is 21.

Step-by-step explanation:

‎‎‎‎‎‎

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME ASAP I NEED TO DO THIS
yarga [219]

Answer:

1. D

Step-by-step explanation:

8 0
2 years ago
heyyy! i haven't posted a question in a long time lolz. anyways, i really needed help with this!! if you can answer my question
Andre45 [30]
2 ones and 8 hundredths

00.00
the first zero is tens, ones, and after the decimal, to the right is the tenths, hundredths and so on
7 0
2 years ago
A football player is running the length of a 100 yard long football field. For the first part of the field, he runs at a rate of
notka56 [123]

Answer:

\frac{2}{5}th part of the field is covered in the second sprint.

Step-by-step explanation:

A football player is running the length of a 100 yard long football field.

Let player sprints x yards with the speed = 2 yards per second.

So time taken to cover x yards player will take time = \frac{x}{2} seconds

Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = \frac{Distance}{Speed}

= \frac{100-x}{4} seconds

Now total time taken by the player can be represented by the equation

\frac{x}{2}+\frac{100-x}{4}=40

Now we can solve this equation for the value of x.

\frac{2x+100-x}{4}=40

x + 100 = 40×4

x + 100 = 160

x = 160 - 100 = 60 yards

And length of the second part will be = 100 - 60 = 40 yards

Now the fraction of the field covered by the player in second sprint will be

= \frac{40}{100}

= \frac{2}{5} or 40%

Therefore, \frac{2}{5}th part of the field was covered in second sprint.

5 0
3 years ago
Find the sum of a finite geometric sequence from n = 1 to n = 6, using the expression −2(5)n − 1.
vazorg [7]
\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=-2\\
r=5\\
n=6
\end{cases}
\\\\\\
S_6=-2\left( \cfrac{1-5^6}{1-5} \right)
8 0
3 years ago
Read 2 more answers
Other questions:
  • 7 5/8 + 2 9/16. Can u plz help me I can't figure it out
    14·2 answers
  • Are the ratios 21/149 and 30/70 equivalent explain pls help
    11·2 answers
  • How many days between 09/26/16 and 10/04/2016?
    8·1 answer
  • The number $75$ is decreased by $40\%$, then the result is again decreased by $40\%$. What is the final result?
    11·1 answer
  • Need help pleaseeee!!!
    10·1 answer
  • Becky took out an 80/20 mortgage on a $167,000 home. What is the amount
    9·2 answers
  • 10 - 13x - 7 -8x =6 need help
    7·2 answers
  • Suppose you wanted to make an open-topped box out of a flat piece of cardboard that is 25 inches long
    15·2 answers
  • Can anyone help me fill this out please :( . <br> I’ll mark you as a brainliest:) .
    7·2 answers
  • Find the measure of each angle indicated (quadrilaterals)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!