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PilotLPTM [1.2K]
3 years ago
12

Please answer the question above.

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0

Answer:

5.3!

Step-by-step explanation:

( in case you need work ) the angles are congruent so you set them equal to each other!

6x+12=9x-4

you then get 16=3x then divided its 5.3!

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167+57 written in base ten method
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Quadratic inverse for y=x^2-1
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let's recall that to find the inverse of any expression, we start off by doing a quick switcheroo on the variables, and then solve for "y".

\bf y = x^2-1\implies \stackrel{switcheroo}{x=y^2-1}\implies x+1=y^2\implies \sqrt{x+1}=\stackrel{f^{-1}(x)}{y}

8 0
2 years ago
Donata bought 4 lemons and 4 plums at the local supermarket for a total of $ 21.60. Dan bought 11 lemons and 6 plums at the same
VashaNatasha [74]
  1. you must establish a equation system  with the information given , 4x numbers of limon , where x represent the cost of every lemon and 4y numbers of plums , where y represents the cost of plums
  2. now  the equation system is 1) 4x+ 4y = 21,60 and 2) 11x+ 6y = 40.29
  3. of the equation 1 you must obtain the value of x, 4x = 21.60+4y ⇒x=21.60/4+4y/4⇒x= 5.4+y
  4. now with the value of x , it is substitute in the equation 2)   11(5.4+y) + 6y = 40.29 , ⇒ 59.4 + 11y + 6y = 40.29 ⇒  17y = 40.29-59.4⇒ y = -19,11/7⇒ y = -2.73
  5. the value of y is substitute in the equation 1) x = 5.4 + ( -2,73)⇒ x= 2,67,  where ,the price of every lemon is $ 2,67
6 0
3 years ago
Hey guys,<br><br> Do you guys know the answer to this TTM problem?<br><br> Thank You!
tensa zangetsu [6.8K]
I think it is 2.5,2.5
4 0
3 years ago
It takes 22 hours for a hosepipe with a flow of 12 litres per minute to fill a swimming pool. How long will it take if its flow
Monica [59]

Answer:

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

Step-by-step explanation:

The volume of the swimming pool can be written as;

Volume V = flow rate × time

V = R×t

V = R1×t1 = R2×t2

R1×t1 = R2×t2

t2 = R1×t1/R2 ........1

Given;

Flow rate R1 = 12 litres per minute

Flow rate R2 = 5 litres per minute

time t1 = 22 hours

Substituting the given values into equation 1;

t2 = R1×t1/R2 = 12×22/5

t2 = 52.8 hours

it will take 52.8 hours if its flow is reduced to 5 litres per minute.

3 0
3 years ago
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