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strojnjashka [21]
3 years ago
15

Please help me wit these 2

Mathematics
1 answer:
Sedaia [141]3 years ago
5 0

Answer:

6)GFE

EFG

F

4

8) I got x=1

Step-by-step explanation:

So sorry if that is wrong

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If the diameter of a men’s basketball is 10 inches and a women’s is 9 inches, what is the approximate difference of their volume
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Answer:

1

Step-by-step explanation:

10-9

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HELP QUICK
Jobisdone [24]

Answer:

0.055

Step-by-step explanation:

You want to move the decimal from the % left two places.

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I need to make a matrix in reduced row echelon form
a_sh-v [17]

Let the three apartments be A, B & C

The rent of A is $x

The rent of B is $y

The rent of C is $z

So x + y + z = 1600     .......(1)

Now

Maintenance of A is 20% of x = 0.20x

Maintenance of B is 20% of y = 0.20y

Maintenance of C is 25% of z = 0.25z

0.20x + 0.20y + 0.25z = 345

Multiplying by 100 we get

20x + 20y + 25 z = 34500

Dividing by 5 we get

4x + 4y + 5z = 6900              .......(2)

Monthly fee of A is 10% of x = 0.10x

Monthly fee of B is 20% of y = 0.20 y

Monthly Fee of C is 10% of z = 0.10z

Now

0.10x + 0.20y + 0.10 z= 1820 - 1600

0.10x + 0.20y + 0.10z = 220

Multiplying by 100 we get

10x + 20y + 10z = 22000

Dividing by 10

x + 2y + z = 2200     ....(3)

Making a Matrix of equation (1), (2) & (3)

\left[\begin{array}{ccc}1&1&1\\4&4&5\\1&2&1\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right]  =\left[\begin{array}{c}1600\\6900\\2200\end{array}\right]

is the required matrix

7 0
4 years ago
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What will most likely happen to a characteristic that has a high survival value in a population?
Levart [38]
The characteristic will spread and be more common throughout populations.
6 0
3 years ago
A factory produces 80,000 candies each day. They produce equal quantities of four favors: cherry,lemon,orange,and strawberry. Th
Nostrana [21]

Answer:

0.25 is the probability that the randomly selected candy is orange.

Step-by-step explanation:

We are given the following in the question:

Total number of candies = 80,000

Four equal number of flavored candies:

cherry,lemon,orange,and strawberry

Thus, number of orange candies =

= \dfrac{\text{Total number of candies}}{4}\\\\=\dfrac{80000}{4} = 20000

Thus, 20,000 orange flavored candies are produced.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

P(orange) =

=\dfrac{\text{Number of orange candies}}{\text{Total number of candies}}\\\\=\dfrac{20000}{80000} = \dfrac{1}{4} = 0.25

0.25 is the probability that the randomly selected candy is orange.

6 0
3 years ago
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