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3 years ago

Simpify the expression 7-x (-5x)-10 4x

1 answer:

8 0

Step 1. Gather like terms

 $7-(-5x*x)-10,4x
$

Step 2. Use Product Rule: $x^{a} x^{b} = x^{a+b}$

$7-(5 x^{2} )-10,4x$

Step 3. Simplify brackets

$7+5 x^{2} -10,4x$

Step 4. Simplify $7+5 x^{2} -10$ to $5x^{2} -3$

$5 x^{2} -3,4x$

7+5{x}^{2}-10

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What is the area of LMN

irakobra [83]

4 square units.

The easiest way to find this is by looking at the triangle as if NL was the base. In this case PM would be the height. Since a triangle is the same shape even when we move it or rotate it, this is a common strategy to finding areas when the direction is tough for us.

Now that we have this we can measure the lengths of the base and height and use them in the triangle area formula.

Base = 4

Height = 2

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Area of a triangle = 1/2(4)(2)

Area of a triangle = 2(2)

Area of a triangle = 4

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3 years ago

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3 years ago

Jacob spent 7 hours skiing and snowboarding. He skied for 3 hours 55 minutes.

netineya [11]

Answer:

3 hours 5 minutes

Step-by-step explanation:

Had he skied 5 minute longer, he would have skied for 4 hours, leaving 3 hours for snowboarding. Since he skied 5 minutes less than 4 hours, he snowboarded 5 minutes more than 3 hours.

You can also just subtract the times.

7 hours - 3 hours 55 minutes =

= 6 hours 60 minutes - 3 hours 55 minutes

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2 years ago

For which of the following is the arc between the two hands of a clock greater than a semicircle?

Kazeer [188]

Answer:

Step-by-step explanation:

Each hour is 30 degrees. 11 to 6 is 7 hours so 30 * 7 = 210 degrees, which is greater than a semicircle, which is 180 degrees.

6 0

3 years ago

Read 2 more answers

Use the table of integrals, or a computer or calculator with symbolic integration capabilities, to find the indefinite integral.

nignag [31]

Answer:

$-\frac{3}{11}\ln(\cot t + \csc t)+C$

Step-by-step explanation:

We are given: $\int \frac{3}{x\sqrt{121-x^2}} dx$

We will use integration by parts.

$x = 11 \sin t\\dx = 11 \cos t \: dt$

$\int \frac{3}{x\sqrt{121-x^2}} dx=\int \frac{3* 11 \cos t \: dt}{11 \sin t\sqrt{121-121\sin^2 t}} =\int \frac{3* 11 \cos t \: dt}{11 \sin t*11\cos t}} =\\\\= \frac{3}{11} \int \csc t = -\frac{3}{11}\ln(\cot t + \csc t)+C$

4 0

4 years ago