For which of the following is the arc between the two hands of a clock greater than a semicircle?
2 answers:
Answer:
A. The hands are at 11 and 6; arc measured clockwise
Step-by-step explanation:
A semicircle measures 180º and when you measure the distance from 11 to 6 the difference in the hands of the clock by each hour is given by the equation:
= 30
So there are 7 numbers between the 11 and the 6 if you measure it clockwise, that means that the angle formed by the two hands of the clock measured clockwise is:
7*30= 210
Wich is greater than 180º, which is why that is the correct answer.
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Answer:
The value of x must be greater than 100.
Step-by-step explanation:
We need to find the value x for which the value of log(x) is greater than than 2.
According to the property of logarithm, if a is a real number.
Using the above property of logarithm, the given inequality can be rewritten as
We conclude that the value of log(x) is greater than 2 for real values of x which are greater than 100.
Therefore, the value of x must be greater than 100.