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3 years ago

For which of the following is the arc between the two hands of a clock greater than a semicircle?

Mathematics

2 answers:

Lesechka [4]3 years ago

8 0

Answer:

A. The hands are at 11 and 6; arc measured clockwise

Step-by-step explanation:

A semicircle measures 180º and when you measure the distance from 11 to 6 the difference in the hands of the clock by each hour is given by the equation:

$\frac{360}{12}$ = 30

So there are 7 numbers between the 11 and the 6 if you measure it clockwise, that means that the angle formed by the two hands of the clock measured clockwise is:

7*30= 210

Wich is greater than 180º, which is why that is the correct answer.

Kazeer [188]3 years ago

6 0

Answer:

Step-by-step explanation:

Each hour is 30 degrees. 11 to 6 is 7 hours so 30 * 7 = 210 degrees, which is greater than a semicircle, which is 180 degrees.

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3 years ago

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3 years ago

Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d

iogann1982 [59]

<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144

Solution:

Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.

for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!

for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d

they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>

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