PLEASE HELP ASAP PLEASE WILL MARK BRAINIEST

-2x + y=10. what is the answer to this? y=-1/3x+3

juin [17]

Answer:

x = - 3, y = 4

Step-by-step explanation:

Given the 2 equations

- 2x + y = 10 → (1)

y = - $\frac{1}{3}$ x + 3 → (2)

Substitute (2) into (1), that is

- 2x - $\frac{1}{3}$ x + 3 = 10 ( multiply through by 3 to clear the fraction )

- 6x - x + 9 = 30

- 7x + 9 = 30 ( subtract 9 from both sides )

- 7x = 21 ( divide both sides by - 7 )

x = - 3

Substitute x = - 3 into (2) for corresponding value of y

y = - $\frac{1}{3}$ (- 3) + 3 = 1 + 3 = 4

solution is x = - 3, y = 4

4 0

3 years ago

Which logarithmic equation is equivalent to the exponential equation below? ea = 35

Cerrena [4.2K]

a = ln(35) I believe is the correct answer. If correct brainliest answer plz

5 0

3 years ago

Read 2 more answers

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

4 years ago

The volume of a rectangular prism is given by the expression10x3 + 46x2 – 21x – 27. The area of the base of the prism is given b

kondor19780726 [428]

H = V / B
= 10x3 + 46x2 – 21x – 27 / 2x^2 + 8x - 9
= 5x + 3

8 0

4 years ago

Read 2 more answers

Solve -9 2/7 - (10 3/7)

Setler [38]

Answer:

add the whole numbers. -9+10=1

1 2-3/7

remove one digit from the whole number:. 1-1=0

add the denominator to 2=7+2=9

:. 9-3/7=6/7

answer=6/7

3 0

3 years ago