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jarptica [38.1K]
3 years ago
9

1) Draw an activity diagram according to the below flow of event:

Computers and Technology
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

Yyyyttttrrttyuynynnyj6jj

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.Visual Studio .NET’s ___________ feature displays all the members in a class
Alex

Answer:d)Intellisense

Explanation: Visual Studio.NET is the tool for the development of the application .Intellisense is the type of code that is found in the Visual Studio.NET which is used for the intelligent completion of text or code. The factors present in the Visual studio NET has are tracking of the values, increasing the understanding of code,presenting the class member etc.

Other options are incorrect because real time error checking is for the checking of the error raising at the time of execution, Quick info is for gaining data rapidly and outlined code are for display of the hierarchical structure of codes.Thus, the correct option is option(d).

3 0
3 years ago
Isabel is creating a wireframe. She has drawn a layout for the home page along with outlining the navigation elements. She now w
Juli2301 [7.4K]

Answer: Filler content

Explanation: I think what the question is getting at is using filler content. This includes filler images and sample text. Once the website is all set up, the filler content is replaced with the actual content.

3 0
3 years ago
Read 2 more answers
Which of these field types allows multiple, non-exclusive options?
AlexFokin [52]

Question:

Which of these field types allows multiple, non-exclusive options?

A. multi-part

B. checkbox

C. text

D. radio button

E. button

Answer:

The correct option is B) Checkboxes

Explanation:

Field types is a terminology often associated with Database Management.

A field type is often found in a data collection apparatus such a form. It's inherent quality or nature will determine the kind of data that it can collect.

Some field types allow for exclusive options. That is, in some data field types, it's impossible to select more than one option.

For example, a Button field type can only collect one type of value.

A Checkbox on the other can be configured to allow for multiple selections which may or may not be exclusive.

When working with Microsoft Access, for instance, you are required to select the name of the <em>field </em>and define the type of <em>field data.</em>

<em />

Cheers!

6 0
3 years ago
Given a string variable string 's;', implement a tokenizer to identify the unique tokens contained in this string, identify all
Flauer [41]

Answer:

#include <iostream>

#include <string>

#include <vector>

#include <cctype>

#include <algorithm>

using namespace std;

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols);

struct TokenFreq{

string token;

int freq;

};

string spaces(string& istr, string& newstr);

void printVector(vector<TokenFreq> & tfVec);

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVecVec);

void selectionSort( vector<TokenFreq> & tokFreqVector );  

void insertionSort( vector<TokenFreq> & tokFreqVector );

//main

int main(int argc, const char * argv[]) {

 

vector<vector<int> > matrix;

matrixInit(matrix, 3, 4);

 

string ostr1 = " I do keep the main points straight in my head most of the time, and I do know where to find the details when I need them. by Bjarne Stroustrup";

string ostr2 = " ";

string ostr3 = "Your time is limited, so don’t waste it living someone else’s life.Stay Hungry. Stay Foolish.";

//string ostr = ostr2;

string istr;

 

cout << "Enter the text: ";

getline(cin, istr);

vector<TokenFreq> tfVec;

getTokenFreqVec(istr, tfVec);

selectionSort(tfVec);

insertionSort(tfVec);

return 0;

}

//-----

void selectionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int min;

 

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

min = i;

for (int j = i+1; j <int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq < tokFreqVector[min].freq)

min = j;

}

if(min!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[min];

tokFreqVector[min] = temp;

}

}

cout<<"-----selectionSort------------------"<<endl;

printVector(tokFreqVector);

}

void insertionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int max;

 

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

max = i;

for (int j = i+1; j < int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq > tokFreqVector[max].freq)

max = j;

}

if(max!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[max];

tokFreqVector[max] = temp;

}

}

cout<<"-----insertionsort------------------"<<endl;

printVector(tokFreqVector);

}

string spaces(string& istr, string & newstr){

int j;

//Check double space and create new string with lowercase

for (int i = 0; i < int(istr.length()); ++i){

istr[i] = tolower(istr[i]);

if (isspace(istr[i])){

//check double space again

j = i+1;

while(true){

if (istr[j] == '\342') istr[j]=' ';

if (istr[j] == '\200') istr[j]=' ';

if (istr[j] == '\224') istr[j]=' ';

if(isspace(istr[j])) j++;

else break;

}

i=j-1;

newstr = newstr + istr[i];

}else

newstr = newstr + istr[i];

}

return newstr;

}

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVec){

string newstr;

int curr_beg = 0;

int curr_end = 0;

string word;

bool check = false;

int index=0;

 

//call func spaces to get new string

newstr = spaces(istr, newstr);

//cout << newstr << endl;

//cout << endl;

//cout << newstr << "||" << endl;

string tempstr = newstr;

 

if(newstr != " "){

tfVec.push_back(TokenFreq());

}

for (int i = 0; i < int(newstr.length()); ++i){

if(isspace(newstr[i])){

check = false;

 

curr_end = i;

word = tempstr.substr(curr_beg, curr_end - curr_beg);

curr_beg = i + 1;

 

for (int j = 0; j < int(tfVec.size()); j++){

if (tfVec[j].token == word){

tfVec[j].freq++;

check = true;

 

break;

}

}//end-for;

if (check == false && i!=(int(newstr.length())-1)){

//cout <<"**"<< word <<"**"<<word.length()<< endl;

tfVec[index].token=word;

tfVec[index].freq=1;

index++;

tfVec.push_back(TokenFreq());

}

word = "";

//add last value

}

}//end-for

 

if(!isspace(newstr[int(newstr.length())-1])){

word = tempstr.substr(curr_beg, curr_end - (int(newstr.length())-1));

tfVec[index].token=word;

tfVec[index].freq=1;

//tfVec.push_back(TokenFreq());

}

 

printVector(tfVec);

}

void printVector(vector<TokenFreq> & tfVec){

 

cout << "size= {" << tfVec.size() << endl;

for (int i = 0; i < int(tfVec.size()); i++){

cout << " [" << i << "] = (token = \""<< tfVec[i].token <<"\", freq = " << tfVec[i].freq << ")" << endl;

//cout << tfVec[i].token<<endl;;

}

cout << endl;

}

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols){

int i;

int j;

matrix.resize(numRows, vector<int>(numCols) );

for(i = 0; i< numRows; i++ ){

for(j = 0; j < numCols; j++ )

matrix[i][j] = i*j;

}

 

cout << "size of matrix is: " << numRows << "x" << numCols << endl;

for (i = 0; i < numRows; i++){

for (j = 0; j < numCols; j++){

cout<< "matrix[" << i << "][" << i << "]=" << matrix[i][j] << endl;

}

}

cout << endl;

}

Explanation:

3 0
3 years ago
Homework 8 Matlab Write a function called fibonacciMatrix. It should have three inputs, col1, col2, and n. col1 and col2 are ver
Amiraneli [1.4K]

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is:

<em>function v = myfib(n,v)</em>

<em>if nargin==1</em>

<em>    v = myfib(n-1,[0,1]);</em>

<em>elseif n>1</em>

<em>    v = myfib(n-1,[v,v(end-1)+v(end)]);</em>

<em>end</em>

<em>end</em>

<em>function v = myfib(n,v)</em>

<em>if nargin==1</em>

<em>    v = myfib(n-1,[0,1]);</em>

<em>elseif n>1</em>

<em>    v = myfib(n-1,[v,v(end-1)+v(end)]);</em>

<em>elseif n<1</em>

<em>    v = 0;</em>

<em>end</em>

<em>function [n] = abcd(x)</em>

<em>if (x == 1 || x==0)</em>

<em>    n = x; </em>

<em>    return</em>

<em>else</em>

<em>    n = abcd(x-1) + abcd(x-2);</em>

<em>end</em>

<em>end</em>

<em>fibonacci = [0 1];</em>

<em>for i = 1:n-2</em>

<em>    fibonacci = [fibonacci fibonacci(end)+fibonacci(end-1)];</em>

<em>end</em>

<em>>> myfib(8)</em>

<em>ans =</em>

<em>    0    1    1    2    3    5    8   13</em>

<em>>> myfib(10)</em>

<em>ans =</em>

<em>    0    1    1    2    3    5    8   13   21   34</em>

See more about python at  brainly.com/question/18502436

8 0
2 years ago
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