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Fofino [41]
2 years ago
13

A 12 foot ladder is leaning against a wall and the foot of the ladder is 5 feet away from the wall. What is the angle between th

e ground and the ladder
Mathematics
1 answer:
Pepsi [2]2 years ago
8 0

Answer:

65.38degrees

Step-by-step explanation:

Given the following

Length of ladder = 12foot = hypotenuse

Distance of the ladder from the wall = 5ft = adjacent

Required

Angle between the ground and the ladder theta

Using the SOH CAH TOA identity

Cos theta = adj/hyp

Cos theta = 5/12

Cos theta = 0.41667

theta = arccos(0.41667)

theta = 65.38 degrees

Hence the angle between the ground and the floor is 65.38degrees

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<h2>\large\bold{\underline{\underline{Question:-}}}</h2>

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1 show that their volumes are in the ratio 3 : 1.

<h2>\large\bold{\underline{\underline{Solution:-}}}</h2>

⇒ Ratio of heights of two cones = 1 : 3

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⇒ We know that V = 1/3πr²h

⇒ Ratio of their volume = V1 : V2

\underline{ \underline{ \sf{Let's \:  find  \: the  \: ratio  \: of \:  their  \: volumes:}}}

{ \implies{ \sf  {V _{1}  :  V_{2}}}}

{ \implies{ \sf{ \frac{1}{3} \pi \:  { r_{1}}^{2}  h_{1} :  \frac{1}{3}  \pi \:  { r_{2} }^{2}  h_{2}}}}

{ \implies{ \sf{ {r_{1}}^{2}  h_{1} :  { r_{2}}^{2} h_{2}}}}

{ \implies{ \sf{ \frac{ { r_{1} }^{2} }{ { r_{2} }^{2} }  :  \frac{ h_{2} }{ h_{1} } }}} \\

{ \implies{ \sf{ \frac{ {3}^{2} }{ {1}^{2} }  :  \frac{3}{1} }}} \\

{ \implies{ \sf{ \frac{9}{1} :  \frac{3}{1}  }}} \\

{ \implies{ \sf{3 : 1}}} \\

{ \therefore{ \sf{ \green{Ratio  \: of  \: their \:  volumes = 3 : 1}}}}

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