The actual dimension of the sail are 6 m tall and 4.5 m wide.
The model is 20 cm tall. First we need to find the ratio which Kendall used in his model.
6 meters of actual length is represented in model by 20 cm.
6 meters of actual length is represented in the model by 0.2 m.
1 meter of actual length is represented in the model by 0.2/6 = 1/30 meters
So, the ratio of actual measure to model measure will be:
1 : 1/30
or
30 : 1
The actual width of the sail = 4.5 meters
The width of the sail in the model will be = 4.5 x 1/30 = 0.15 m = 15cm
So, the dimensions of the sail in the model will be 20 cm tall and 15 cm wide.
Answer:
lower bound = 90 - 10 = 80 cm
upper bound = 90 + 10 = 100 cm
lower bound d = 1500 x 80 cm = 120,000 cm
upper bound d = 1500 x 100 cm = 150,000 cm
P(A) = 0.993 is the probability of event A
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P(A) is the probability of not A (note that I am trying to place a bar over A. I hope you can see it, else it is because the editor did not show it as I intended)
Then, use the fact that the probability of A plus the probability not A is equal to 1:
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=> P(A) + P(A) = 1
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=> P(A) = 1 - P(A) = 1 - 0.993 = 0.007
So, the answers are:
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1) P(A) = 0.07
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2) Yes, A is unlikely because its probability is very low.
I don’t know how you think this is a opinion
