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3 years ago

What is the largest integer value of x in the solution of the following inequality? 2x-5<-17

Mathematics

1 answer:

cupoosta [38]3 years ago

4 0

Answer:

The answer is 8

Step-by-step explanation:

u have to do the simplest

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Jan has a 12 ounce milkshake four ounces in the milkshake are vanilla and the rest is chocolate what are two equivalent fraction

vlada-n [284]

Four ounces out of 12 ounces would be 4/12, or simplified form that would be 1/3, and the rest is 8/12, or 2/3.

6 0

4 years ago

Read 2 more answers

PLEASE HELP ME!!!!!!!!

olga55 [171]

Answer:

B. segment DE, segment EF, and segment DF are all different lengths, and the slopes of segment DE and segment EF opposite reciprocals

Step-by-step explanation:

I just took the test.

6 0

3 years ago

Write the equation 2x 2 - 4x + 6 = 1 in standard form and then choose the value of "c."

Karolina [17]

It is 5
2x2 -4x +6-1= 0 is the standard form

6 0

3 years ago

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Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for th

NeX [460]

As long as Loren drove, the law of motion was

$200 = st_1 \implies t_1 = \dfrac{200}{s}$

As long as Loid drove, the law of motion was

$100 = (s-10)t_2 \implies t_2 = \dfrac{100}{s-10}$

So, the total time they took is

$t_1+t_2=\dfrac{200}{s}+\dfrac{100}{s-10}$

Had Loren driven the whole time, the law of motion would have been

$300=st_3 \implies t_3 = \dfrac{300}{s}$

And we know that this time would have been 30 minutes (i.e. 0.5 hours) faster. So, we have

$t_3 = t_1+t_2-0.5$

This translates into

$\dfrac{300}{s}=\dfrac{200}{s}+\dfrac{100}{s-10}-\dfrac{1}{2}$

If we subtract 200/s from both sides, we have

$\dfrac{100}{s}=\dfrac{100}{s-10}-\dfrac{1}{2}$

We can simplify the right hand side by summing the two fractions:

$\dfrac{100}{s-10}-\dfrac{1}{2} = \dfrac{200-(s-10)}{2(s-10)}=\dfrac{210-s}{2(s-10)}$

So, we have to solve

$\dfrac{100}{s}=\dfrac{210-s}{2(s-10)}$

If we cross multiply the denominators, we have

$200(s-10)=s(210-s) \iff 200s-2000=210s-s^2 \iff s^2-10s-2000=0$

Which yields the solutions

$s=-40,\quad s=50$

We accept the positive solution, because the negative would mean to travel backwards, so Loren's rate was 50mph

5 0

3 years ago

Read 2 more answers

It is 3/5 mile from Elaine's home to her school. It is 1/10 mile from her home to the library. How much farther is Elaine's home

Kipish [7]

3/5 is equivalent to 6/10

the school is 6/10 miles away
the library is 1/10 miles away

6/10-1/10=5/10

From her home to her school is 5/10 or 1/2 a mile farther than from her home to the library

6 0

3 years ago