For 1.999 × 2.4, how many decimal hops would you move (right to left) to place in your answer?

Someone help ASAP!!!!!!

Alchen [17]

Answer:

Length, l = 11 ft.

Width, w = 9 ft.

Step-by-step explanation:

From the given data, the area of the rectangle = 99 ft².

Area of the rectangle = Length, l X Width, w

Here, Length, l = 7 more than twice the width

⇒ Length, l = 7 + 2w

Therefore, Area, A = 99 = (7 + 2w)w

⇒ 99 = 7w + 2w²

⇒ 2w² + 7w - 99 = 0

Solve the Quadratic equation using the formula: x = $\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ for the quadratic equation ax² + bx + c = 0.

Therefore, w = $\frac{-7 \pm \sqrt{7^2 -4(2)(-99)}}{2(2)}$

$= \frac{-7 \pm \sqrt{49 + 8(99)}}{4}$

$= \frac{-7 \pm + \sqrt{841}}{4}$

Since, $\sqrt{841} = 29$ we get:

$w = \frac{-7 \pm 29}{4}$

This gives two values of 'w', viz., w = $\frac{-7 - 29}{4}$ , $\frac{-7 + 29}{4}$

$\implies w = \frac{22}{4}, \frac{-36}{4}$

⇒ w = $\frac{22}{4}$ , -9.

We take the integer values.

If w = -9, then l = 2(-9) + 7

⇒ l = - 18 + 7 = - 11

Therefore, the length, l of the rectangle = - 11 ft.

and the width, w of the rectangle = - 9 ft.

Hence, the answer.

3 0

3 years ago

Daily high temperatures in St. Louis for the last week were as follows: 95, 92, 93, 92, 95, 90, 90 (yesterday). a) The

hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as follows:

95, 92, 93, 92, 95, 90, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the 2-day moving average

Solution:

a)

- The set of 3 day moving average is as follows:

4. (95 + 92 + 93) ÷ 3 = 93.33⁰C

5. (92 + 93 + 92) ÷ 3 = 92.33⁰C

6. (93 + 92 + 95) ÷ 3 = 93.33⁰C

7. (92 + 95 + 90) ÷ 3 = 92.33⁰C

8. (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3. (95 + 92) ÷ 2 = 93.5⁰C

4. (95 + 93) ÷ 2 = 92.5⁰C

5. (93 + 92) ÷ 2 = 92.5⁰C

6. (92 + 95) ÷ 2 = 93.5⁰C

7. (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

Error Error^2

3. 93.5⁰C 0.5 0.25

4. 92.5⁰C 0.5 0.25

5. 92.5⁰C 2.5 6.25

6. 93.5⁰C 3.5 12.25

7. 92.5⁰C 2.5 6.25

8. 90⁰C

- The mean absolute deviation as follows:

MAD = Sum of all errors / 5

MAD = (0.5+0.5+2.5+3.5+2.5) / 5

MAD = 1.9

d)

- The mean squared error deviation as follows:

MSE = Sum of all error^2 / 5

MSE = (0.25+0.25+6.25+12.25+6.25) / 5

MSE = 5.05

4 0

3 years ago

The circumference of circle p is 800 mm, the circumference of circle q is 200 cm, and the circumference of circle r is 4 m. What

shepuryov [24]

Let us use the following conversions:

1 cm = 10 mm

1 meter = 100 cm = 1000 mm

Given:

p = 800 mm

q = 200 cm = 2000 mm

r= 4 m = 4000

X = sum of the distance around each circle

X = p+q+r

X = 800+2000+4000

7 0

3 years ago

Is the graphed function linear?

masha68 [24]

Answer:

please provide an image of the graph

8 0

2 years ago

X+3/3=y+2/2,then x/3=

Nina [5.8K]

It would equal 3
i hope this helps

4 0

3 years ago