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LiRa [457]
3 years ago
10

Are the fractions 1/3 and 3/9 equivalent?

Mathematics
2 answers:
Zigmanuir [339]3 years ago
6 0
Yes it is equivalent if u multiply 1 times 3 u get 3 if u multiply 3 times 3 is 9 so they r equivalent hope this help:)<span />
CaHeK987 [17]3 years ago
6 0
Yes, the fractions are equivalent.
in order to solve this problem, you need both fractions to have the same denominators.
ask yourself if 3 can go into 9. it can.
you change the denominator of 3 to 9. but when you change the denominator, you also have to change the numerator. since 3 goes into 9 three times, you also multiply the numerator by 3. 
1/3 times 3/3 equal 3/9. since 3/9 and 3/9 are the same, they are equivalent
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PLEASE ANSWER AS QUICK AS POSSIBLE
Lady_Fox [76]

Answer:

  (a)  h^-1(x) = (x+6)/6

Step-by-step explanation:

The inverse relation can be found by solving for y: x = h(y).

<h3>Solution</h3>

  x = h(y) . . . . . the inverse relation

  x = 6y -6 . . . . . use the function definition

  x +6 = 6y . . . . add 6

  (x +6)/6 = y . . . . divide by 6

The inverse function is ...

  \boxed{h^{-1}(x)=\dfrac{x+6}{6}}

4 0
2 years ago
The airport security randomly selected 36 suitcases from the security line. Of these bags, they screened 8 suitcases. Based on t
castortr0y [4]

The ratio of suitcases to screened suitcases is 36:8. The second ratio is 180:?.

--

180 is 5 times 36 which can be proven by dividing 180 by 36.

180 ÷ 36 = 5

Multiply 5 by 8 to find the amount of suitcases that would be screened if there were 180 total suitcases.

5 × 8 = 40

The first ratio is 36:8, and with a scale factor of 5 we get the second equivalent ratio 180:40.

<h2>Answer:</h2>

<u>Forty suitcases</u><u> will be screened.</u>

I hope this helps :)

4 0
3 years ago
What did I do wrong. I thought it was 15
CaHeK987 [17]
Its not 15 isnt it 10
3 0
4 years ago
Read 2 more answers
Is (4, -1) the solution of the system of equations shown below?
serious [3.7K]

Answer:

yeah

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position
nexus9112 [7]

Answer:

\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60

Step-by-step explanation:

So, we know that:

\tan(\theta)=60/11\text{ and } 90\textdegree

Since θ is in QI, this means that <em>all</em> of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the <em>opposite side to the adjacent side</em>. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

a^2+b^2=c^2

Substitute 60 for a and 11 for b:

60^2+11^2=c^2

Solve for c. Square both numbers:

3600+121=c^2

Add:

c^2=3721

Take the square root of both sides:

c=61

Therefore, the hypotenuse is 61.

So, our side lengths are: Opposite=60; Adjacent=11; and Hypotenuse=61.

Now that we know the lengths, we can find the other trig ratios:

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 60 for Opp and 61 for Hyp:

\sin(\theta)=60/61

Cosecant is the reciprocal of sine. So:

\csc(\theta)=61/60

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 11 for Adj and 61 for Hyp:

\cos(\theta)=11/61

Secant is the reciprocal of cosine. So:

\sec(\theta)=61/11

Tangent and Cotangent:

We are already given that tangent is:

\tan(\theta)=60/11

Cotangent is the reciprocal of tangent. So:

\cot(\theta)=11/60

4 0
4 years ago
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