For this, we use simultaneous equations. Let George's page be g, Charlie's be c and Bill's page be b.
First, <span>George's page contains twice as many type words as Bill's.
Thus, g = 2b.
</span><span>Second, Bill's page contains 50 fewer words than Charlie's page.
Thus, b = c - 50.
</span>If each person can type 60 words per minute, after one minute (i.e. when 60 more words have been typed) <span>the difference between twice the number of words on bills page and the number of words on Charlie's page is 210.
We can express that as 2b - c = 210.
Now we need to find b, since it represents Bill's page.
We can substitute b for (c - 50) since b = c - 50, into the equation 2b - c = 210. This makes it 2(c - 50) - c = 210.
We can expand this to 2c - 100 - c = 210.
We can simplify this to c - 100 = 210.
Add 100 to both sides.
c - 100 + 100 = 210 + 100
Then simplify: c = 210 + 100 = 310.
Now that we know c, we can use the first equation to find b.
b = c - 50 = 310 - 50 = 260.
260 is your answer. I don't know where George comes into it. Maybe it's a red herring!</span>
3²×7................................................
Answer:
C 1/2
Step-by-step explanation:
There are 4 suits, 2 suits are red (hearts and diamonds) while 2 are black (clubs and spades)
Since 13 cards are in each suit, 26 cards are red ( 2 * 13)
There are 52 total cards
P (red) = red cards/ total cards
= 26 / 52
= 1/2
(3.7 x 104)2 = 769.6
In Scientific notation:
7.696 x 10^2
Answer:
9.80 m
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the relationship between sides of a right triangle and its angles.
__
<h3>setup</h3>
The geometry of this problem can be modeled by a right triangle, so these relations apply. We are given an angle and adjacent side, and asked for the opposite side, so the relation of interest is ...
Tan = Opposite/Adjacent
Using the given values, we have ...
tan(24°) = AC/AB = (tree height)/(distance from tree)
tan(24°) = AC/(22 m)
<h3>solution</h3>
Multiplying by 22 m gives ...
tree height = AC = (22 m)·tan(24°) ≈ 9.79503 m
The height of the tree is about 9.80 meters.
