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4 years ago

Which expressions are solutions to the equation (3/4)x = 15? Select all that apply.

Mathematics

1 answer:

marshall27 [118]4 years ago

7 0

Answer:

Step-by-step explanation:

(3/4)x=15

x=15 ÷ 3/4

x=20

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I think ots a fair car tbh

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3 years ago

Read 2 more answers

*Need Help?!!!! Question I'm stuck on!!!

Ahat [919]

1.) It is D) $106.20

46020 / 52 (because she's paid weekly) = 885
7% + 5% = 12%
885 x .12 = 106.2

2.) It is D) $106.20

46020 / 52 (because she's paid weekly) = 885
7% + 5% = 12%
885 x .12 = 106.2

3.) He will pay $500 + $2000, or $2500.

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3 years ago

Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo

svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

$PV = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}} \end {bmatrix}$

$128000 = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

$PV= 921.433 \begin {bmatrix} \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

PV = $121718.2714

C) In order to estimate how many payments of $1400 it will take to pay off the loan, we have:

$121718.2714 = \begin {bmatrix} \dfrac{1300 (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}} \end {bmatrix}$

$121718.2714 = 200000 \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$\dfrac{121718.2714}{200000 } = \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$0.60859 = \begin {bmatrix} (1 - \dfrac{12}{12.078}))^{nt} \end {bmatrix}$

$0.60859 = (0.006458)^{nt}$

$nt = \dfrac{0.60859}{0.006458}$

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88 - 177795.38

The amount of interest saved = $153920.5

6 0

4 years ago

Simplify 8 to the -5th power over 8 to the -3rd power

svetoff [14.1K]

Answer:

the first one

Step-by-step explanation:

i had that question

4 0

4 years ago

The sum of two numbers is 30 and their difference is 12. Find the two numbers.

MariettaO [177]

Answer:

let the two numbers are x & y

x+y=30...eq(1) &x-y=12....eq(2)

x=30-y then put in the eq(2)

30-y-y=12

30-2y=12

-2y=12-30

-2y= -18

y=9 then we put this answer in to eq(1)

so,x+y=30

x+9=30

x=30-9

x=21

so, the two numbers are (21,9)

5 0

4 years ago