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madreJ [45]
3 years ago
7

Anyone I’m really lost

Mathematics
1 answer:
Savatey [412]3 years ago
3 0

Answer:

The answer is option 3.

Step-by-step explanation:

You have to substitute H+=2×10^(-9) into the equation of pH :

pH = -log[H+]

H+ = 2×10^(-9)

pH = -log[2×10^-9]

= 8.70 (3s.f)

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PLEASE HELP ....................​
lesantik [10]

Answer:

a. SAS

b. SSS

c. SSA

d. AAS

e. SAS

f. ASA

g. ASA

h. SAS

Step-by-step explanation:

8 0
2 years ago
Fill in the missing work and justification for step 2 when solving 3(x + 2) = 12.
liq [111]

Answer:

2

Step-by-step explanation:

3(x+2)=12

Distribute:

3x+6=12

Subtract:

3x+6-6=12-6

3x=6

Divide:

x=2

4 0
3 years ago
What is the are a square with a side length of 3x + 4.
geniusboy [140]
(3x + 14) (3x + 14) = 9x^2 + 24x + 16
3 0
2 years ago
Can you solve this? :)
Nina [5.8K]
The answer is B.
X = -11 :-)
8 0
3 years ago
Read 2 more answers
A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ 
E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ 
P(E^{c})= \frac{3}{12} \\  \\ 
P(E^{c})= \frac{1}{4}
7 0
3 years ago
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