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3 years ago

Find the value of x that makes Triangle DEF~ triangle XYZ.

Mathematics

1 answer:

BartSMP [9]3 years ago

8 0

Answer:

x = 4

Step-by-step explanation:

DE / XY = EF / YZ

5 / 10 = 2x-1 / 14

cross-multiply:

10(2x-1) = 14(5)

20x - 10 = 70

20x = 80

x = 4

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The figure shows the path of a track. It consists of a semicircular arc BCD and three sides of a rectangle in which AB = 20 cm,

fredd [130]

$\large \mathcal{Answer}$

A. Area of given figure = 280 + 77 = 357 cm²

B. length of semicircle = 22 cm

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3 years ago

Resolute academy algebra 1

Goryan [66]

Answer:

Step-by-step explanation:

We can see in the expression that there are 2 x² blocks, 4 -x blocks, and 3 -1 blocks. Therefore, we can write this as

2 * x² + 4 * (-x) + 3 * (-1) = 2x²-4x-3

Comparing this with each answer, we have

A: x²-2x-4 + x² + 2x-1 = 2x²-5. This is not correct

B: 3x²-7x+1-(x²-3x+4) = 3x²-7x+1 -x²+3x-4 = 2x²-4x-3. This seems correct but we can check the other answers to be sure

C: (2x+1)(x-3) = 2x²-6x+x-3 = 2x²-5x-3. This is incorrect

D: $\frac{8x^{12} - 16x^7 - 12x^6}{4x^6} = 2x^6 - 4x - 3$ . This is incorrect

3 0

3 years ago

Find 4 + (-1 2/3)and write the answer in its simplest form

SIZIF [17.4K]

11/3

Mark brainliest please

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3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

For this problem, we consider that we want it to be within 4%.

Item a:

The sample size is n for which M = 0.04.

There is no estimate, hence $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2$

$n = 600.25$

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is $\pi = 0.96$ , hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}$

$\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2$

$n = 92.2$

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to $\pi = 0.5$ , the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151

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2 years ago

Tutoring ABC charges $50 sign up fee plus $12 an hour . HW helps charge a $38 sign up fee plus $15 an hour . After how many hour

tamaranim1 [39]

Answer:

Step-by-step explanation:

Tutoring ABC - $50 sign up and $12 an hour

HW helps- $38 sign up and $15 an hour

50 38

+12 +15

62 53

+12 +15

74 68 Four months

+12 + 15

86 83

+12 +15

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2 years ago