Answer:
Jayce should not use either option. Option 1 is likely to be based so that paperbacks are overrepresented, while Option 2 is likely to be biased so that e-books are overrepresented.
Step-by-step explanation:
<em>Given:</em>
<em>Jayce volunteers for the local library. The librarian wants to find out whether the patrons prefer paperback books or e-books. Jayce cannot decide which method to use for polling the patrons.</em>
<em>Option 1: Poll every fifth patron who enters the library on Paperback Lovers Day.</em>
<em>Option 2: Poll every third patron who enters the library on Technology Appreciation Day.</em>
<em />
<em>Since, Option 1: Poll every fifth patron who enters the library on Paperback Lovers Day. It biased because since it paperback lovers day thus, it would be likely that most people like the paperback which make it biased.</em>
<em>Since, Option 2: Poll every third patron who enters the library on Technology Appreciation Day. It biased because since it technology appreciation day thus, it would be likely that most people don't care about these stuff since people coming in are for technology appreciation.</em>
<em />
<em />
<em>Therefore, the answer is:</em>
Jayce should not use either option. Option 1 is likely to be based so that paperbacks are overrepresented, while Option 2 is likely to be biased so that e-books are overrepresented.
<u><em>Kavinsky</em></u>
Answer:
-11
Step-by-step explanation:
You need to take the absolute value of 12-15 which would be 3. Then take -8-3 which would be -11
Answer:
16 Miles
Step-by-step explanation:
For every week you simply multiply the number of miles from the previous week by 2, therefore
Week 1: 1
Week 2: 2
Week 3: 4
Week 4: 8
Week 5: 16
Side XZ needs to be congruent to side AC. The answer is D.
Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes
so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so
x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero
x³=0
x=0
x-∛3=0
x=∛3
x²+x∛3+∛9=0 has no solution
x+∛3=0
x=-∛3
x²-x∛3+∛9=0 has no solution
so the solutions are
x=-∛3, 0, ∛3
