The expression which can be rewritten using a common factor is; xy/10 (x² + 2y).
<h3>What is an expression?</h3>
Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
We have the following information given as;
One tenth times x cubed times y plus two tenths times x times y squared using a common factor.
We know that 'times' has to be replaced with multiplication.
Now, we will change this into mathematical expression as;
x³y/ 10 + 2xy²/ 10
Now, the common factor can be ;
xy/10
The Common factor refers to the number and the variables taken as a common factor should be able to completely divide the terms given any expression.
Now, taking it as a common factor, we have the following expression:
xy/10 (x² + 2y)
Hence, the required expression is; xy/10 (x² + 2y).
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Answer:
you +1 on each side
Step-by-step explanation:
a is 30-1=7
b is 32=8
to get from "a" to "b" you simply add one on both sides
32 - 1 = 7
+ 1 +1
------------------
32=8
<span><span>Solve <span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120 </span></span>><span><span> 0</span>. </span></span><span>First, I factor to find the zeroes:<span><span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120</span><span>= (x + 5)(x + 3)(x + 1)(x – 2)(x – 4) = 0</span></span><span>...so </span><span>x = –5, –3, –1, 2,</span><span> and </span>4<span> are the zeroes of this polynomial. (Review how to </span>solve polynomials, if you're not sure how to get this solution.)<span>To solve by the Test-Point Method, I would pick a sample point in each interval, the intervals being </span>(negative infinity, –5)<span>, </span>(–5, –3)<span>, </span>(–3, –1)<span>, </span>(–1, 2)<span>, </span>(2, 4)<span>, and </span>(4, positive infinity). As you can see, if your polynomial or rational function has many factors, the Test-Point Method can become quite time-consuming.<span>To solve by the Factor Method, I would solve each factor for its positivity: </span><span>x + 5 > 0</span><span> for </span><span>x > –5</span>;<span>x + 3 > 0</span><span> for </span><span>x > –3</span><span>; </span><span>x + 1 > 0</span><span> for </span><span>x > –1</span><span>; </span><span>x – 2 > 0</span><span> for </span><span>x > 2</span><span>; and </span><span>x – 4 > 0</span><span> for </span><span>x > 4</span>. Then I draw the grid:...and fill it in:...and solve:<span>Then the solution (remembering to include the endpoints, because this is an "or equal to" inequality) is the set of </span>x-values in the intervals<span> [–5, –3]<span>, </span>[–1, 2]<span>, and </span>[4, positive infinity]</span>. </span>
As you can see, if your polynomial or rational function has many factors, the Factor Method can be much faster.
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Answer:
1.37 miles
Step-by-step explanation:
If she went along 1/10 of the trail, multiply that fraction times the length of the trail
1/10 * 13.7
13.7/10
Move the decimal 1 place to the left since we are dividing by 10
1.37 miles
Answer: C
Step-by-step explanation:
I remember this test