Write the standard equation of a circle that passes through (1, −6) with center (7, −2).
1 answer:
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Answer:
Step-by-step explanation:
If the area is
and area = length * width and our width is given as x + 4, then the length is found by dividing the area by the width. You could do that using long division, but it's easier using synthetic division.
-4 | 1 -2 -40 -64
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1
This is how you start. The -4 inside the box comes from the factor you are dividing by. If x + 4 = 0, then x = -4. The numbers after are the coefficients from each descending power of x. Multiply the -4 by the 1 and put that product up under the -2 and add to get:
-4 | 1 -2 -40 -64
-4
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1 -6
Now multiply -4 by -6 and put that product up under the -40 and add:
-4 | 1 -2 -40 -64
-4 24
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1 -6 -16
Multiplying -4 by -16 gives you 64 so when you add you get a remainder of 0.
The numbers under the line give you the depressed polynomial
That gives you the expression for the length. That's C.