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Dimas [21]
3 years ago
13

Write the standard equation of a circle that passes through (1, −6) with center (7, −2).

Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

D: (x – 7)2 + (y + 2)2 = 52

Step-by-step explanation:

Circle: (x -h)² + (y - k)² = r²    center (h , k)    r: radius

(1 , -6) on the circle: radius   √(1 - 7)² + (-6 - (-2))² = √36 + 16 = √52

(x -7)² + (y +2)² = (√52)² = 52

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Find the x-intercept and y-intercept of the equation. Then graph the equation using the intercepts.
pentagon [3]

Answer:

The answer to your question is:

Step-by-step explanation:

                                              y = -3x + 16/3

Find y-intercept

To find it, x = 0

                                             y = -3(0) + 16/3

                                             y = 0 + 16/3

                                             y = 16/3 ≈ 5.3   The point is (0, 16/3)

Find x-intercept

y = 0

                                            0 = -3x + 16/3

                                            -16/3 = -3x

                                            x = -16/3/-3

                                            x = 16/9 ≈ 1.8  The point is (1.8, 0)

We look for these points in the axis and finally join them.

                     

3 0
4 years ago
Read 2 more answers
Plz help me I really need help
swat32

Answer:

it 2 parts away

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Evaluate each expression. Determine if the final simplified form of the expression is positive or negative -42 (-4)2 42
Sati [7]

Answer:

Given the expression:

1.

-4^2

we know:

4^2 = 4 \times 4 = 16

then;

-4^2 = -16

Therefore, the value of expression -4^2 is -16 i.e negative.

2.

(-4)^2

we know:

4^2 = 4 \times 4 = 16

(-1)^2 = 1

then;

(-4)^2 = (-1)^2 \cdot (4)^2= 16

Therefore, the expression (-4)^2 is 16 i.e Positive.

3.

4^2

we know:

4^2 = 4 \times 4 = 16

then;

4^2 = 16

Therefore, the expression 4^2 is 16 i.e Positive.


8 0
3 years ago
Prove each of these identities.
Stella [2.4K]

Answer:

Identity (a) can be re-written as

sec x\ cosec x  - cot x = tan x

which we already proven in another question, while for idenity (b)

(A)\frac 1 {sin x} -sin x = cos x \frac{cos x}{sin x}\\\\(B)\frac {1-sin^2x}{sin x} = \frac {cos^2x} {sin x} \\\\(C) \frac {cos^2x}{sin x} =\frac {cos^2x} {sin x}

step A is simply expressing each function in terms of sine and cosine.

step B is adding the terms on the LHS while multiplying the one on RHS.

step C is replacing the term on the numerator with the equivalent from the pithagorean identity cos^2x  + sin^2x = 1

8 0
2 years ago
Janis jogs around a rectangular park that is mi
Fynjy0 [20]

Answer:

  1 7/10 miles

Step-by-step explanation:

Halfway around the park is ...

  (3/5 mi) +(1/4 mi) = 12/20 mi +5/20 mi = 17/20 mi

Then all the way around the park is ...

  2×17/20 mi = 17/10 mi = 1.7 miles

It is 1.7 miles around the park.

8 0
3 years ago
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