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3 years ago

Solve the following 5/4-72/12+1/3

1 answer:

6 0

You have to find a common denominator. 12 is the easiest to get in this case. 5/4 * 3= 15/12, 1/3 * 4=4/12. 15/12-72/12+4/12. The answer is 53/12

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Please help with this

klemol [59]

Answer:

(h+k)(2)=4+1+2-2=5

(h-k)(3)=9+1-3-2=3+1-1=9

3h2+2k3=3*5+2=17

7 0

3 years ago

1. Simplify: 4(4y-7y^{2})-9(5y+2) 2. Simplify: 24 – 4(5y – 6z) + 3y – 7z

Greeley [361]

Answer:

1)-

How to solve your question

Your question is

4(4−72)−9(5+2)

4(4y-7y^{2})-9(5y+2)4(4y−7y2)−9(5y+2)

Simplify

Rearrange terms

4(4−72)−9(5+2)

4({\color{#c92786}{4y-7y^{2}}})-9(5y+2)4(4y−7y2)−9(5y+2)

4(−72+4)−9(5+2)

4({\color{#c92786}{-7y^{2}+4y}})-9(5y+2)4(−7y2+4y)−9(5y+2)

Distribute

4(−72+4)−9(5+2)

{\color{#c92786}{4(-7y^{2}+4y)}}-9(5y+2)4(−7y2+4y)−9(5y+2)

−282+16−9(5+2)

{\color{#c92786}{-28y^{2}+16y}}-9(5y+2)−28y2+16y−9(5y+2)

Distribute

−282+16−9(5+2)

-28y^{2}+16y{\color{#c92786}{-9(5y+2)}}−28y2+16y−9(5y+2)

−282+16−45−18

-28y^{2}+16y{\color{#c92786}{-45y-18}}−28y2+16y−45y−18

Combine like terms

−17y+17z+24

See steps

Step by Step Solution:

STEP1:Equation at the end of step 1

((24 - 4 • (5y - 6z)) + 3y) - 7z

STEP2:

Final result :

-17y + 17z + 24

−282+16−45−18

-28y^{2}+{\color{#c92786}{16y}}{\color{#c92786}{-45y}}-18−28y2+16y−45y−18

−282−29−18

-28y^{2}{\color{#c92786}{-29y}}-18−28y2−29y−18

Solution

−282−29−18

4 0

2 years ago

If w = 12 units, x = 7 units, and y = 8 units, what is the surface area of the figure? Figure is composed of a right square pyra

bearhunter [10]

Answer:

720 sq units.

Step-by-step explanation:

Length and width of square prism, w = 12 units

Height of square prism, x = 7 units

Height of square pyramid, y = 8 units

Please have a look at the attached image.

Here 2 Surfaces will not be exposed which are base of the square pyramid and the top of the square prism i.e. 2 square surfaces will not be exposed.

Here, surface area of the composite figure will be:

Surface Area of Composite Figure = Lateral surface area of Square Pyramid + Surface Area of 5 surfaces of the square prism

For finding the lateral surface area of pyramid, we need to find the slant height of the pyramid.

Let slant height be $l$ units.

Using pythagoras theorem, we can find out the value of $l$ .

As per theorem:

$Hypotenuse^{2} = Base^{2} + Height^{2}\\$

$\Rightarrow l^{2} = (\dfrac{w}{2})^{2} + y^{2}\\\Rightarrow l^{2} = (\dfrac{12}{2})^{2} + 8^{2}\\\Rightarrow l^{2} = {6}^{2} + 8^{2}\\\Rightarrow l^{2} = 36+64 = 100\\\Rightarrow l = 10\ units$

Lateral surface area of square prism = 4 $\times$ Area of triangular surface

$\Rightarrow 4 \times \dfrac{1}{2}\times Base \times Slant\ Height\\\Rightarrow 4 \times \dfrac{1}{2} \times 10 \times 12\\\Rightarrow 240\ sq\ units$

Surface Area of 5 surfaces of the square prism =

$4 \times x \times w + w^2\\\Rightarrow 4 \times 12 \times 7 + 12^2\\\Rightarrow 336 +144\\\Rightarrow 480\ sq\ units$

So, total surface area of composite figure:

240 + 480 = 720 sq units.

7 0

2 years ago

ASAP ASAP PLS ASAP Asapppppp

zaharov [31]

Tell Me if I'm Wrong But I Believe It's 198m3

6 0

2 years ago

Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 4 at x = −3 and a local minimum value of 0 at

Vinvika [58]

The formula is f(x) = a x ^ 3 + b x ^ 2 + c x + d
f '(x) = 3ax^2 + 2bx + c.
f(- 3) = 3 ==> - 27a + 9b - 3c + d = 3
f '(- 3) = 0 (being a most extreme) ==> 27a - 6b + c = 0.
f(1) = 0 ==> a + b + c + d = 0
f '(1) = 0 (being a base) ==> 3a + 2b + c = 0.
-
Along these lines, we have the four conditions
- 27a + 9b - 3c + d = 3
a + b + c + d = 0
27a - 6b + c = 0
3a + 2b + c = 0
Subtracting the last two conditions yields 24a - 8b = 0 ==> b = 3a.
Along these lines, the last condition yields 3a + 6a + c = 0 ==> c = - 9a.
Consequently, we have from the initial two conditions:
- 27a + 9(3a) - 3(- 9a) + d = 3 ==> 27a + d = 3
a + 3a - 9a + d = 0 ==> d = 5a.
Along these lines, a = 3/32 and d = 15/32.
==> b = 9/32 and c = - 27/32.
That is, f(x) = (1/32)(3x^3 + 9x^2 - 27x + 15).

8 0

3 years ago