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OLEGan [10]
3 years ago
14

I will give Brainiest if your right

Mathematics
1 answer:
Monica [59]3 years ago
3 0

Answer:

f

Step-by-step explanation:

sum of 15 and -6 is 11

-3 times -2 is 6 because the negatives cancel out

6 plus the 5 left in the parenthesis is 11

brainiest pls

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The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.410.410, point, 4 years; th
Neko [114]

Answer:

99.7%

Step-by-step explanation:

The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.4 years; the standard deviation is 1.9 years.

Use the empirical rule (68−95−99.7%) to estimate the probability of a meerkat living between 4.7 years and 16.1 years

The empirical rule states that almost all data fall within three standard deviations of the mean for a normal distribution. These are:

  1. 68% of data falls within the first standard deviation from the mean ( μ ± σ)
  2. 95% fall within two standard deviations ( μ ± 2σ)
  3. 99.7% fall within three standard deviations( μ ± 3σ)

Given that:

mean (μ) = 10.4 years and standard deviation σ = 1.9 years

The first standard deviation ( μ ± σ) = (10.4 ± 1.9) = (8.5, 12,4). Therefore, 68% of data falls between 8.5 years and 12.4 years

The second standard deviation ( μ ± 2σ) = (10.4 ± 2×1.9) = (6.6, 14.2). Therefore, 95% of data falls between 6.6 years and 14.2 years

The third standard deviation ( μ ± 3σ) = (10.4 ± 3×1.9) = (4.7, 16.1). Therefore, 99.7% of data falls between 4.7 years and 16.1 years

8 0
3 years ago
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Jeff is standing on top of a tree next to a mysterious monolith (a big rectangular box). At time t = 0, Jeff threw a coconut ver
zimovet [89]

Answer:

h=\frac{h_{m}-h_{t}+44.145}{3}t-4.905t^{2}+h_{t}

(if the heights are measured in meters)

Step-by-step explanation:

In order to solve this problem we will need to first draw a diagram of the situation (see attached picture) and then, make use of the following physics equation:

y_{f}=\frac{1}{2}at^{2}+v_{0}t+y_{0}

where:

y_{f}=height of the object at a given time t

a=acceleration due to gravity

t=time

v_{0}=initial velocity of the object

y_{0}=initial height of the object.

we know most of this data, except for the height of theh object at the given time t and the initial velocity of theh object. We can make use of the given time to write the velocity in terms of the height of thte tree and the height of the monolith.

So let's substitute the values we know so far:

h=\frac{1}{2}(-9.81)t^{2}+v_{0}t+h_{tree}

the problem tells us that after 3 seconds, the object reaches the height of the monolith, so let's do the substitution:

h_{monolith}=\frac{1}{2}(-9.81)(3)^{2}+v_{0}(3)+h_{tree}

we can now solve this equation for the initial velocity, so we get:

h_{monolith}-h_{tree}=-44.145+3v_{0}

h_{monolith}-h_{tree}+44.145=3v_{0}

so:

v_{0}=\frac{h_{monolith}-h_{tree}+44.145}{3}

and now we can substitute this back into the original formula to get the equation that represents the height of the coconut above the ground after t seconds:

h=\frac{h_{m}-h_{t}+44.145}{3}t-4.905t^{2}+h_{t}

3 0
3 years ago
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