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iVinArrow [24]
4 years ago
12

6492x82You also have to borrow Plz help

Mathematics
2 answers:
ELEN [110]4 years ago
7 0
532,344
Hope that is what you were looking for.
musickatia [10]4 years ago
3 0
Yes I agree with that and I hope you pass that
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A plane is flying at 31,348 feet. It needs to rise to 36,000 feet in two stages. In stage 1, it rises 5% of its initial altitude
In-s [12.5K]

Answer:

well, 5% of 31348 is 1567.4

That leaves her 3084.6 feet to go.

And as you know, time = distance/speed

Step-by-step explanation:

6 0
3 years ago
HELP HURRY pls
Bess [88]

Please see the explanation of this question to see procedure for the dilation of the triangle ABC and the image attached below to know the result.

<h3>How to generated a resulting triangle by transformation rules</h3>

In this question we must apply a kind of <em>rigid</em> transformation known as dilation. A dilation of a point around a point of reference is defined by the following operation:

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]     (1)

Where:

  • O(x, y) - Point of reference
  • k - Dilation factor
  • P(x, y) - Original point
  • P'(x, y) - Resulting point

Let assume that the point P is the origin of a <em>rectangular</em> system of coordinates. Then, the coordinates of the three vertices of the triangle ABC respect to the origin are: A(x, y) = (- 1, 2), B(x, y) = (- 1, - 1), C(x, y) = (2, 0).

Then, the vertices of the resulting triangle A'B'C' are, respectively:

A'(x, y) = (0, 0) + 3 · [(- 1, 2) - (0, 0)]

A'(x, y) = (- 3, 6)

B'(x, y) = (0, 0) + 3 · [(- 1, - 1) - (0, 0)]

B'(x, y) = (- 3, - 3)

C'(x, y) = (0, 0) + 3 · [(2, 0) - (0, 0)]

C'(x, y) = (6, 0)

Finally, we draw the resulting triangle with the help of a graphing tool.

To learn more on dilations: brainly.com/question/13176891

#SPJ1

7 0
2 years ago
What is 50% of 49.99
Contact [7]
<span>25 is 50% of 49.99
..................................</span>
3 0
3 years ago
Read 2 more answers
-5/8 multiplied by 7/1
astraxan [27]

Answer:

-4.375

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In adjoining figure a circle is inscribed in the quadrilateral ABCD given that BC is equal to 38 cm cube is equal to 27 cm and B
lukranit [14]

<h3>Radius = 14cm</h3>

Step-by-step explanation:

Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC

Also, AD ⊥ DC (given), therefore, OPDS is a square.

BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)

therefore, CR = CB - BR = (38 - 27)cm = 11cm

SC = CR = 11 cm...(tangents from an external point) therefore, DS = DC - SC = (25 - 11) cm = 14 cm.

therefore,

Radius of a circle = OP = DS = 14 cm...(therefore, OPDS is a square).

<h3>Hope it helps you!! </h3>
5 0
3 years ago
Read 2 more answers
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