We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
Properties in math are used as general rules to solve problems.
I hope this helped!
Step-by-step explanation:
600 * .34 = 204 are in 8th grade
204 * 1/4 = 51 51 8th graders walk to school
D
Average = Mean
To find the mean, add up the numbers and divide it by how many numbers there are.
So,

There are 5 numbers in total.

To do these types of division, ignore the decimal and add a 0 at the end.
So we can do:

And put back the decimal.
Hope this helps :)
Answer:4
Step-by-step explanation:
It’s 4