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4 years ago

The slopes of vertical lines and horizontal lines are opposite reciprocals

Mathematics

2 answers:

Nitella [24]4 years ago

5 0

True! The slopes are opposite reciprocals (aka perpendicular lines)

Scrat [10]4 years ago

5 0

This is true slopes are vertical and horizontal lines are opposite reciprocals.

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Find the average rate of change of g(x)= 7x^4+7/x^3 on the interval [2,3]

joja [24]

7x^4 +7/x^2 on the interval [-2,3]

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3 years ago

A jar of natural peanut butter normally cost $4.00. Today its on sale for $3.60. What is the percentage of the discount

mafiozo [28]

Answer:

Ambitious

Answer

Find out the what is the percentage of this discount .

To prove

Formula

Discount = Marked price - selling price

As given

a jar of natural peanut butter normally costs $4.00 .

it's on sale for $3.60 .

thus

Marked price = $4.00

selling price = $3.60

put in the above formula

Discount = 4.00 - 3.60

= 0.4

Formula

put the value

Discount percentage = 10%

Option (a) is correct .

Hence proved

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3 years ago

PLS HELP ME ASAP WILL MARK BRAINLIEST!!

My name is Ann [436]

Answer:

1. Rational

2. Integer

3. Irrational

4. Irrational

5. Imaginary

8 0

3 years ago

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

4 years ago

Can someone help me with this please hurry thanks

sertanlavr [38]

Remember you can do anything to an equaiton as long as you do it to both sides

-6g+36=12
minus 36 both sides
-6g=-24
diide -6
remember(-)/(-)=(+)
g=4

5 0

4 years ago

Read 2 more answers