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IgorC [24]
4 years ago
9

(-2t+3)(4t-5) how to do this in quadratic standard form

Mathematics
1 answer:
zloy xaker [14]4 years ago
4 0

Answer:

−8t^2+ 22t −15

Step-by-step explanation:

Hope that helps

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If the book fair had a sale where 6 books were $20.46 then if you wanted 7 books how much money would you need
lianna [129]

Answer:

If you wanted to buy 7 books you would need $23.87.

Step-by-step explanation:

Divide the total of the six books by their price, ($20.46/6), you would get that the individual price of each book is $3.41. Lastly, you multiply that number by 7 because that's how many books you need (7 x $3.41). You end up with $23.87

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3 years ago
Area of this shape with 2cm and 2cm and 4cm and 7cm
Annette [7]
18cm is the answer of this question
6 0
3 years ago
This is a re-post please help me
Lena [83]

Answer:

10.p=135

11. y=170

12. w=180

13. r=23.5

14. d=0.33

15. r=0.57

16. b=13.5

17. c=1.96

18. d=48.76

Step-by-step explanation:

4 0
3 years ago
How many irrational numbers are there between 1 and 6 ?
Inga [223]

Answer:

The answer is Infinitely many

8 0
3 years ago
Read 2 more answers
7th Grade Math <br><br> Need help with both 6 and 7
barxatty [35]

Answer:

Part 6)

case a) P(odd)=\frac{1}{2}=0.5=50\%

case b) P(less\ than\ 3)=\frac{0}{8}=0=0\%

Part 7)

case a) P(yellow)=\frac{3}{20}=0.15=15\%

case b) P(green\ and\ red)=\frac{1}{20}=0.05=5\%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

P=\frac{x}{y}

Part 6)

case a) P(odd)

In this problem we have

x=4

y=8

substitute

P=\frac{4}{8}=\frac{1}{2}=0.5=50\%

case b) P (less than 3)

In this problem we have

x=0

y=8

substitute

P=\frac{0}{8}=0=0\%

Part 7)

case a) P(yellow)

In this problem we have

x=3

y=20

substitute

P=\frac{3}{20}=0.15=15\%

case b) P(green and red)

P(green)=\frac{5}{20}

P(red)=\frac{4}{20}

therefore

P(green\ and\ red)=\frac{5}{20}*\frac{4}{20}=\frac{20}{400}=\frac{1}{20}=0.05=5\%

8 0
3 years ago
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