Area of this shape with 2cm and 2cm and 4cm and 7cm

Mathematics

1 answer:

Annette [7]3 years ago

6 0

18cm is the answer of this question

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P pennies added to 22 pennies

taurus [48]

23 Pennie’s is the answer I believe

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A box contains 35 coins either nickels or dimes all worth $2.90. How many dimes are in the box?

tino4ka555 [31]

Answer:

There are 23 dimes in the box

Step-by-step explanation:

Let nickels=n

Let dimes=(35-n)

Equation: 0.05n+0.10(35-n)=2.90

Multiply both sides by 100: 5n+10(35-n)=290

-5n+350=290

-5n=-60

n=12

35-12=23

Therefore, there are 23 dimes in the box

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3 years ago

What is the best estimate for the product of 289 and 7

Katarina [22]

I would estimate it as (300 x 7) = 2100

Then I would subtract (11 x 7) + 77 from that to get the exact answer of 2023

~~~~~~~~~~
I didn't use a calculator or paper. The 'trick' is to notice that 289 = (300 - 11)

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lutik1710 [3]

The answer is 15 cookies and 5 brownies

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Read 2 more answers

The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow

Reika [66]

If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now $\bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
0=\frac{3w^2-6000000}{w^2}
\end{cases}$

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the $0=w^2\implies 0=w$ so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0

3 years ago