When written in standard form, you have to order each term from the highest degree to the lowest degree.
b. x^4y² + 4x²y + 8x is your answer.
hope this helps, God bless!
Hey there, Nancykkxx00!
To solve the equation
![x \div 4 - 6 = 2](https://tex.z-dn.net/?f=x%20%5Cdiv%204%20-%206%20%3D%202)
In backward problem-solving strategy, you first need to, if there are no parenthesis, either add or subtract first from both sides.
Here we have a negative 6 ( -6 ), so since we are doing it backwards, instead of subtracting 6, we are adding 6 to both sides.
![x \div 4 - 6 + 6 = 2 + 6](https://tex.z-dn.net/?f=x%20%20%5Cdiv%204%20-%206%20%2B%206%20%3D%202%20%2B%206)
![x \div 4 = 8](https://tex.z-dn.net/?f=x%20%5Cdiv%204%20%3D%208)
( The six from the left side cancels out making it 0 )
Now we move to division. Since we are diving (we always have yo do the opposite of what we are doing), we need to multiply. So,
![x \div 4 \times 4 = 8 \times 4](https://tex.z-dn.net/?f=x%20%5Cdiv%204%20%5Ctimes%204%20%3D%208%20%5Ctimes%204)
Always do it on both sides.
Now, we end up with
![x = 32](https://tex.z-dn.net/?f=x%20%3D%2032)
If we plug it in, it will be like this
![(32) \div 4 - 6 = 2](https://tex.z-dn.net/?f=%2832%29%20%5Cdiv%204%20-%206%20%3D%202)
![8 - 6 = 2](https://tex.z-dn.net/?f=8%20-%206%20%3D%202)
![2 = 2](https://tex.z-dn.net/?f=2%20%20%3D%202)
So, the answer is
![x = 32](https://tex.z-dn.net/?f=x%20%3D%2032)
Thank you for using Brainly.
See you soon!
The LCM of 4 and 14 would be 28, all you have to do is put all multiples of both numbers and find the FIRST common one. So like this:
4, 8, 12, 16, 20, 24, 28
14, 28
So basically in small terms all u do is find the first multiple that BOTH numbers have and it has to be the same.
Answer:
value of x = 5.8 mm
Step-by-step explanation:
We have given,
Two right triangles EDH and EDG.
In right triangle EDH, EH = 56mm , DH = 35 mm
Using Pythagoras theorem we can find ED.
i.e EH² = ED²+DH²
56²=ED²+35²
ED²=56²-35²
ED = √(56²-35²) = 7√39 = 43.71 mm
Now, Consider right triangle EDG
Here, EG=44.8mm , GD = x+4 and ED = 7√39
Again using Pythagoras theorem,
EG² = ED² + DG²
44.8²= (7√39)²+ (x+4)²
(x+4)² = 44.8² - (7√39)²
x+4 = √(44.8² - (7√39)²)
x+4 = 9.8
or x = 9.8 - 4 = 5.8 mm
Hence we got the value of x = 5.8 mm
Answer:
61 years old
Step-by-step explanation:
26 plus 3 is 29 and 29 times 3 is 87 and 87 minus 29 is 61