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Airida [17]
3 years ago
15

MATHS - 10 POINTS HCF/LCM thankyou!!

Mathematics
1 answer:
zlopas [31]3 years ago
6 0
LCM

10,000|2
5,000|2
2,500|2
1,250|2
625|5
125|5
25|5
5|5
1

24,000|2
12,000|2
6,000|2
3,000|2
1,500|2
750|2
375|3
125|5
25|5
5|5
1

LCM(10000,24000)=2^6\cdot3\cdot5^4=120,000
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Select the correct vectors.
Paha777 [63]

In the case above, the correct vectors are:

  • <25.98, -15>.
  • <1.71, 4.7>.

<h3>What is the ship vector about?</h3>

The solution for the Ship's vector are:

Note that the Horizontal aspect = 30 cos 30  

                                                   = 25.98.

For the  Vertical aspect = 30 sin(-30)

                                        = -15.

Hence it will be  <25.98, -15>.

In regards to the current's vector:

The Horizontal aspect=  5 sin 20

                                       = 1.71.

The Vertical aspect = 5 cos 20

                                     = 4.7.

Hence it will be <1.71, 4.7>.

Therefore, In the case above, the correct vectors are:

  • <25.98, -15>.
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Learn more about vectors from

brainly.com/question/23973576

#SPJ1

4 0
1 year ago
What is the number of subsets of S= {1, 2, 3…10} that contain five element include 3 or 4 but not both?
Ivenika [448]

Answer:

140

Step-by-step explanation:

To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.

First, let's count the number of subsets that contain the element 3.

Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is {}_8C_4=70.

Now, let's count the number of subsets that contain the element 4.

4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in {}_8C_4=70 ways.

We conclude that there are 70+70=140 required subsets of S.

7 0
3 years ago
I need anyone's help please, I'm stuck and its timed.
aivan3 [116]

Answer:

the flagpole is 33 feet high.

Step-by-step explanation:

Brainliest please :)

6 0
3 years ago
2.4 more than the product of -1.2 and a number is below zero
kotykmax [81]
The biggest number is 2.4 because if you take 1/2 that's have
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16 divided by 5 as a decimal
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