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3 years ago

Find the indicated function values for the function below g(x)=9x + 8 g(0) =

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

6 0

Answer:

$g(0) = 8$

Step-by-step explanation:

The problem gives us the following function:

$g(x) = 9x + 8$

g(0) =

This is the value of g when x = 0. So

$g(x) = 9x + 8$

$g(0) = 9*0 + 8$

$g(0) = 8$

So the answer to this question is:

$g(0) = 8$

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68=u-11 need help lololo

dem82 [27]

Answer:

Step-by-step explanation:

79-11=68

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8 0

3 years ago

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Which point is part of the solution of the inequality y 2 12x – 11.

Papessa [141]

Answer:

Point (0,0)

Step-by-step explanation:

Given the inequality y > 12x – 11.

We will check which of the given options will be applied for the inequality

A) (1,0)

Substitute with x = 1 and y = 0

0 > 12*1 - 11

0 > 1 ⇒ Wrong

So, Point (1,0) is not part of the solution of the inequality.

B) (3,2)

Substitute with x = 3 and y = 2

2 > 12*3 - 11

0 > 25 ⇒ Wrong

So, Point (3,2) is not part of the solution of the inequality.

C) (1,1)

Substitute with x = 1 and y = 1

1 > 12*1 - 11

1 > 1 ⇒ Wrong

So, Point (1,1) is not part of the solution of the inequality.

D) (0,0)

Substitute with x = 1 and y = 0

0 > 12*0 - 11

0 > -11 ⇒ True

So, Point (0,0) is part of the solution of the inequality.

Also, see the attached figure which represents the given inequality

The shaded area represents the solution of the inequality, and we can note that point (0,0) is part of the solution of the inequality

5 0

3 years ago

Identify the correct corresponding parts

andrey2020 [161]

Answer:

The correct corresponding part is;

$\overline {CB}$ ≅ $\overline {CD}$

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment $\overline {CA}$ is congruent to $\overline {CE}$ ( $\overline {CA}$ ≅ $\overline {CE}$ )

Segment $\overline {CB}$ is congruent to $\overline {CD}$ ( $\overline {CB}$ ≅ $\overline {CD}$ )

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment $\overline {AB}$ is congruent to $\overline {DE}$ ( $\overline {AB}$ ≅ $\overline {DE}$ ) by CPCTC

Segment $\overline {AE}$ bisects $\overline {BD}$

Segment $\overline {BD}$ bisects $\overline {AE}$

Therefore, the correct option is $\overline {CB}$ ≅ $\overline {CD}$

3 0

3 years ago

Calculate the averages for each category for the three-month period. category jan. feb. mar. average wages $2,100.00 $2,300.00 $

yan [13]

The averages for each category can be calculated by taking the sum of the values and dividing by the number of values .
Jan Feb March
1)
wages $2,100.00 $2,300.00 $2,000.00
sum of the values = 2100 + 2300 + 2000 = 6400
number of values = 3
average = 6400/3 = $ 2133.33
2)
donations $210.00 $230.00 $200.00
average = (210 + 230 + 200)/3
= $ 213.33
3)
mortgage $590.50 $590.50 $590.50
average = ( 590.50 + 590.50 + 590.50)/3
= $ 590.50
4)
electricity $101.25 $89.75 $80.00
average = (101.25 + 89.75 + 80.00)/3
= 271/3
= $ 90.33
5)
water $20.10 $22.30 $24.55
average = (20.10 + 22.30 + 24.55)/3
= 66.95/3
= $ 22.32
6)
car loan $172.54 $172.54 $172.54
average = (172.54 + 172.54 + 172.54)/3
= $ 172.54
7)
food $200.25 $220.70 $205.50
average = (200.25 + 220.70 + 205.50)/3
= $ 208.82
8)
insurance $310.50 $0.00 $0.00
average = ( 310.50 + 0.00 + 0.00)/3
= $ 103.50
9)
clothes $0.00 $0.00 $75.00
average = (0.00 + 0.00 + 75.00)/3
= $ 25.00
10)
car license fee $0.00 $120.90 $0.00
average = (0.00 + 120.90 + 0.00)/3
= $ 40.30
11)
newspaper $0.00 $0.00 $45.00
average = (0.00 + 0.00 + 45.00)/3
= $ 15.00
12)movies $18.00 $0.00 $36.00
average = (18 + 0.00 + 36.0)/3
= $ 18.00
13)
new car $100.00 $100.00 $100.00
average = (100 + 100 + 100)/3
= $ 100.00
14)
gasoline $80.00 $70.00 $75.00
average = (80.00 + 70.00 + 75.00)
= $ 75.00
15)
car repairs $0.00 $119.00 $0.00
average = (0.00 + 119.0 + 0)/3
= $ 39.67
16)
miscellaneous $64.50 $59.25 $72.50
average = (64.50 + 59.25 + 72.50)/3
= 196.25/3
= $ 65.42
17)
savings $140.00 $140.00 $140.00
average = ( 140 + 140 + 140)/3
= $ 140.00

3 0

3 years ago

A number decreased by six, and then doubled

PIT_PIT [208]

Answer:

Step-by-step explanation:

3 0

3 years ago

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